trivedi: are we still talking just about the profile in your first post?
To take the 450' Vertical Curve as an example:
I computed the surface for a 50 ft. segment:
Station ____ Elev. _______ Slope ______ Description
605975.0 ___ 4393.71 ____ 2.4753% ____ (25 ft. before)
606000.0 ___ 4394.35 ____ 2.4753% ____ near PVI
606025.0 ___ 4395.01 ____ 2.7236% ____ (25 ft. after...for total of 50 ft.)
25A - yes less than 7%
25B - (no cross slope information provided
25C - slope transitions are less than 0.25% in 50 ft. (so they are certainly less than 1% in 6.2 ft)
25D - (information not provided)
25E - (information not provided)
25F - Fig 58:
calculate the slope of the chord from sta 605975-606025: (4395.01-4393.71)/50=2.6%
calculate the elevation of the chord @606000: 25*2.6%+4393.71= 4394.36
difference from surface elevation: 4394.36-4394.35=0.01 ft = 0.12" (less than 7.5"- OK)
(don't see units for 7.5 but you said it is inches)
25G - need to check with 10 ft. straight edge