AS 4100 uses 2.5% (i.e. P / 40). Its predecessor (AS 1250) also used P / 40, and also had a stiffness requirement that the maximum permissible lateral deflection was L / 400, if I recall correctly. The stiffness requirement has been withdrawn in AS 4100. According to the commentary (AS 4100 Supp 1 Clause C6.6.2):
The restraint is required to be able to transfer 2.5% of the axial compression force in the member being restrained, where this is greater than the force specified in Clause 6.6.1. A stiffness requirement is not given even though there is a theoretical solution (Ref. 27). This follows the finding (Ref. 28) that the requirements for centrally braced columns are satisfied by practical braces which satisfy the 2.5% rule.
27 Mutton, B.R., and Trahair, N.S., ‘Stiffness Requirements for Lateral Bracing’, Journal of the Structural Division, ASCE, Vol. 99, No. ST10, Oct. 1973, pp. 2167-2182.
28 Mutton, B.R., and Trahair, N.S., ‘Design Requirements for Column Braces’, Civil Engineering Transactions, Institution of Engineers, Australia, Vol. CE17, No.1, 1975, pp 30-36.
I don’t have a copy of the cited references, but I recall an explanation which goes something like this:
Consider a classic Euler column, with a lateral spring restraint at mid-height. Consider the buckling load in the column as the spring stiffness varies from zero to infinity.
At zero stiffness, the column will be unbraced, with a buckling load of:
Pcrit = pi^2 * E * I / L^2 = P0
At infinite stiffness, the effective length is halved, and the buckling load will be 4 times higher:
Pcrit = pi^2 * E * I / (L / 2)^2 = 4 * P0
At intermediate stiffness, the buckling load will lie between these limits. Therefore, the theoretical objective of a lateral restraint is to be sufficiently stiff that the buckling load approaches the upper limit. The question is – how stiff does the spring need to be?
If you conduct a series of buckling analyses, and plot the result of normalised buckling load (Pcrit / P0) vs. normalised spring stiffness (expressed as spring stiffness / column section stiffness, or k / (E * I / L^3) ), you get a graph something like the attached.
I suspect there is a general closed-form expression, but the important thing to note is that once you have a lateral spiring stiffness greater than about 175 * E * I / L^3, the column is effectively fully laterally restrained. Making the spring even stiffer does not increase the buckling load.
If we return to the old AS 1250 provisions, the implied required lateral spring stiffness is:
k = (P / 40) / (L / 400) = 10 * P / L
Assuming we are designing for the full compression capacity of the braced member (i.e. P = 4 * P0), this expression reduces to:
k = 10 * ( 4 * pi^2 * E * I / L^2 ) / L
which is approximately 395 * E * I / L^3 , which comfortably satisfies the theoretical requirements.
As noted above, the spring stiffness requirement is no longer explicitly stated, but the argument is that “the requirements for centrally braced columns are satisfied by practical braces which satisfy the 2.5% rule”. Personally, I still do a stiffness check as well (i.e. lateral deflection no greater than L / 400 when subject to a lateral load of P / 40, because this is the REAL theoretical requirement.)
Hope this helps!