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quick check calc

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stapulus

Mechanical
Sep 16, 2014
6
If I have a rigid plate with a 240 inch-lb torque applied to it and I have two 1/8" holes each one spaced 1/2" (on centers) away from toque point on opposite sides of the torque, how much would my resistance force have to be at each hole (in inch-lbs) to resist the torque? Thanks!
 
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so there's 1" between the couple forces ... the answer's obvious, no?

another day in paradise, or is paradise one day closer ?
 
assuming, of course, that there's no clamp-up, ie that some of torque is being reacted as a moment under the bolt heads.

another day in paradise, or is paradise one day closer ?
 
Well it seems simple enough but I think a sketch might help clarify things
 
Agreed, it is super simple, its just those simple problems that sometimes make you think am I missing something?
 
link didn't work ...

picture looks pretty useless (we don't hold back here).

it still looks like a couple with an arm of 1" ...

another day in paradise, or is paradise one day closer ?
 
easy there big guy. I couldn't post a photo from my phone so I just sent the url to a photo that would best represent it. it just happened to be on a student site.
 
ok, but when you ask a really basic question and post very crude pix linked to a student site, i think it's understandable.

as i've said already, it still looks like a couple on a 1" arm ... so what's the question ??

another day in paradise, or is paradise one day closer ?
 
There are steel dowels in those 1/8" holes. If the torque of 240 in-lbs is applied to the center of plate, rigid plate, the force acting on each dowel pin is 240Lbf? Is it as easy as that, or am I missing something? Friction negligible.
 
it's pretty much as easy as that !

your pic is showing shear on the dowels, with the torque veector being out-of-plane ... yes?
in which case the answer is correct.

another day in paradise, or is paradise one day closer ?
 
Thanks very much, sometimes it just seems too simple that I start overthinking it.
 
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