Work out required sectional area through deflection limit.
Let W = 20 klf, L = 75', fc' = 6000 psi E = 57√fc' (ksi), Δ ≤ L/300 (in)
Δ = 5WL4/384EI ≤ L/300 ---> I ≥ 1,075,000 in4 = bh3/12
Let h=3b, I = 2.25b4 ≥ 1,075,000 in4 ---> b ≥ 26.3", use 27", and h = 3*27 = 81"
Let d ≈ 0.9h = 73"
WD = 150*27*81)/144000 = 2.3 klf
Wu = 1.4*2.3+1.6*20 = 35.22 klf, say 36
Vu = 36*75/2 = 1350 kips
øVc = 0.75*2*√6000*27*73/1000 = 229 kips
Vs = Vu-øVc/ø = (1350-229)/0.75 = 1495 kips
Vsmax≤ 8√fc'bd = 8√*6000*27*73/1000 = 1221 kips < Vsreq =1495 kips NG --> Increase beam size and fc' to make up the deficit. Ideally, the Vsmax should be kept within 6√fc'bd to avoid congestion of steel.