Use the fact that electric power is equal to mechanical power. Then convert to SI and apply whatever efficiency numbers are valid for the generator type. DC, asynchronous, synchronous or PM type. Below a small DC generator with an assumed efficiency equal to 0.8 and nominal speed 1500 RPM:
n is, of course, 1500 RPM. But you need to use the rad/s speed to find torque. So w = 1500*2*PI/60=157 rad/s
Torque needed is then power/w=1000/157=6.37 Nm
If efficiency is 80 percent, you need to increase torque to 6.37/0.80=7.96, say 8.0 Nm
To guarantee full output at lowest speed you need to use 1500 - 300 RPM. That will increase needed torque correspondingly.
w=126 rad/s torque at 100 % efficiency = 7.96 Nm and, at 80 %, 7,96/0.80=9.95, which is very close to 10 Nm.
The voltage regulation is not your problem, but should not be forgotten. It should also be noted that a PM generator plus an inverter probably is the best way to produce a stable AC or three-phase system from the variable generator output. If your output shall be DC - well, there are several ways to skin that cat also.
Gunnar Englund
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Half full - Half empty? I don't mind. It's what in it that counts.