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Leading-order equation

Leading-order equation

RE: Leading-order equation

Yeah, but the left side of the equation stayed at d^2, should it not become the first derivative after the integration?

RE: Leading-order equation

(d/dz)^2(T) =/= (dT/dz)^2

RE: Leading-order equation

Take the integral in ∂z of both sides, then multiply both integrands by ∂T/∂z , so that the right integral is in ∂T, and you can calculate it as above, and on the left you have (∂T/∂z)2 I cannot explain the factor 2 in the result, though.

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