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# How can I work with the result?

## How can I work with the result?

(OP)
Hi guys,

I'm a beginner, so I'm not very good in the program.
Hopefully somebody can help me :)

My Problem is:

I've got an equation with for example two unknown units.

E.G.

C:= 1/3

0 [strg] = 10F+234-20A-300C

Now, I'd like to change the equation to F.
The result woudl be:

F= -13.4+2A

But the only way I've found to do this with Mathcad is with solve:

0 [strg]= 10F+234-20A-300C solve, F --> -13.4+2A

When I would like to work further with F, it doesn't work like I want it! Because F is not defined ( := )!

How can Mathcad defined the variable F by itself?
I know that I could write F := and than the result, but is not what I like, because than I couldnâ€™t change the other variables and he change the definition of F automatically, because ther is no connection ( i defined it by myself).

The whole reason, why I like to defined the variable F is, that I have to work further!

Hopefully somebody could understand what I'm trying to say ;) and I would be grateful if someone could help me :)

Big thanks

yours

Krankger

### RE: How can I work with the result?

(OP)
Ok maybye I've posted it to early^^
But I did search in LOADS Tutorials and Helpcenters.....

I've just found a solution, but if you ask me I think it's not  the best one. However, it works.

My solution:

F:= 10F+234-20A-300C solve, F --> -13.4+2A

If anybody knows a solution witch is nicer say it to me :)

I do not like that there is the whole equation again, you know?

And another question I've got is it possible to change the result, if you got the arrow before the result? I've tried it with Format--- Results---- and than change the result, but unfortunately it doesn't work.

I've found in a tutorial a solution, so that it works with fload, doesn't it?
Unfortunately it makes my row very long. Yeah I know I can hide the keywords, but do I have to have both keywords? First of all solve and secondly fload or is there any solution to do it shorter?

Big Thanks

### RE: How can I work with the result?

F(A):=0=10F+234-20A-300C solve,F --> 2A-67/5

If I understand your needs correctly, you can enter this formula initially.  Then after you define a value for A you can use F(A) or just use a number for "A".

You could also use...

F(A,C):=0=10F+234-20A-300C solve,F --> 2A+30C-117/5

and then work with both variables.

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