wildalaska
Electrical
- Feb 14, 2013
- 6
I'm trying to model a 12.47 kV distribution system (in the SKM PTW program) with untransposed irregular flat crossarms; maximum line length is about 10 miles.
Typical spacing on flat crossarms is phase A 0", phase B (middle) 26", and phase C 88". No transposing - i.e. phase B stays in the middle. For some sections they did periodically swap phase B from one side of the pole to the other, so then B would be 62" from A and 26" from C, and in the line sections where they did this the line becomes an untransposed (asymmetrical) REGULAR line (in which case the line may be treated as having phase B in the middle, thus simplifying the math somewhat, as A & C become symmetrical with respect to B).
Problem is, PTW, like almost ALL reference sources, assumes that asymmetrical lines are transposed, and even the SKM unbalanced module has no model for untransposed lines.
Review of basics: In an asymmetrical transmission line which has been TRANSPOSED, the three phases are periodically rotated into each position to average the effects of magnetic field cancellation (these unbalances show up as mutual reactances in the impedance matrices). Because of unequal magnetic field cancellation in an untransposed line, phase B has the lowest reactance, followed by whichever phase is closest to B (of course, in a regular untransposed line A & C will have the same reactance).
The standard assumption of a transposed line results in reactances composed of two components: Xa and Xd, where Xa is often called the reactance of the conductor out to 1' and only depends on the conductor's properties (GMR), and Xd is called the "spacing factor" and is the reactance from 1' out to the line separation. For transposed lines the line separation is the GMD = cube root of D1D2D3 (where the D are the line separations), and of course Xd is the same for all 3 phases.
So why not do as most engineers and just ignore the error? I'm tempted. After all, it's on the primary so its effect on the secondary is expected to be small. Well, in the past I would have. But we are now in the era of ARC-FLASH and sometimes either more (by causing extremely intense arcs) or less (by causing overcurrent devices to clear so slowly as to allow the arc to persist too long) AFC can increase the hazard to the point there is no PPE available. I've seen both cases occur ON THE SAME LOW VOLTAGE LINE: Stiff at the beginning, mushy at the end. So one can't always just make assumptions that cause more or less AFC; more accuracy than past practice required seems needed (the IEEE 85% assumption really doesn't help much). So my first question to answer: Is the overhead line asymmetry significant enough that it should not be ignored? I'm thinking if its effect is less than 5% I may ignore it.
Derive asymmetrical spacing factors for phase A case: I know the Ph.Ds go crazy analyzing these types of things, but I'm just a working engineer trying to come up with a model to correctly solve a problem. So using the great old Westinghouse T&D Ref Book, and starting from their derivation of Xd for transposed lines (Chap. 3, pp. 37-39), I derived the following pos & neg seq reactances:
ASSUMPTIONS:
1. Load impedance is balanced and >> line impedance, so that phase currents are approximately balanced and symmetrical.
2. Source voltage is balanced and symmetrical.
3. Line resistance = 0 (since inductance is geometric, we can add R back in later).
4. Ignore zero sequence because all transformers have line-to-line primaries, and arc-flash is only a concern at the low voltage level.
5. Other assumptions are from the Westinghouse text, pp. 34-39.
PHASE A POSITIVE SEQUENCE CASE (i.e. CW rotation):
From Eq 19, p. 37, and being careful to preserve the vector notation (which, for the transposed case, Westinghouse could omit), we have
(Eq1) Ea - E'a = Ia jXa - Ib jXd12 - Ic jXd13
where Xa = self-inductance out to 1' and Xd = spacing factor.
Then,
(Eq 2) ZA+ = jXA+ = (Ea - E'a)/Ia = jXa - (Ib Xd12)/Ia - (Ic Xd13)/Ia
Now, from assumption 1, and remembering that if the phase currents lag the phase voltages by an angle a, this angle a is subtracted out, we note that
- Ib/Ia = 1 @+60 and - Ic/Ia = 1 @-60, so Eq 2 reduces to
(Eq 3) XA+ = Xa + Xd12@+60 + Xd13@-60
Where XA+ is the positive sequence reactance of phase A. Note that where Xd = Xd12@+60 + Xd13@-60, non-zero IM{Xd} implies the existence of a negative or positive (phantom) resistance. Result looks unphysical because X is expected to be just a magnitude, but note that if Xd12 = Xd13 this reduces to the Westinghouse result for symmetrical or transposed lines. If correct, seems to imply the existence of a resistive element, even though the lines were assumed to have no resistance.
PHASE A NEGATIVE SEQUENCE CASE (CCW rotation):
For the negative sequence case, the angle of Vb- = 120 degrees, and the angle of Vc- = 240 degrees. From assumption 1, and once again remembering angle a, we have (note that here the Iabc are neg seq; for notational simplicity we just omitted the "-" from Ia-, etc.)
- Ib/Ia = 1 @ -60 and - Ic/Ia = 1 @ +60, so Eq 2 reduces to
(Eq 4) XA- = Xa + Xd12@-60 + Xd13@+60
Where XA- is the negative sequence reactance of phase A. Again, note that where Xd = Xd12@-60 + Xd13@+60, IM{Xd} implies the existence of a negative or positive (phantom) resistance.
QUESTIONS:
1. Has anyone calculated these things and determined if the asymmetry is significant with regard to arc-flash?
2. Above, I derived the reactances for the pos & neg sequence cases, but the PTW unbalanced module only appears to have an ABC domain Z matrix. Of course, as reactance is purely geometric, line resistance can be added back in at the end (see example below). Also Xa is available from reference books. The conversion from my results to the Z012 matrix, and then from the Z012 to Zabc matrix, looks difficult. Anyone have any slick ideas?
3. Any comments?
Actual line data for 397.5 ACSR, using the above derivation:
0.387133217613171 + j0.608804776800476 ohms/mile = Phase A pos seq Z
0.167670491192792 + j0.587556145614177 ohms/mile = Phase B pos seq Z
0.222196291194038 + j0.661533893295274 ohms/mile = Phase C pos seq Z
0.130866782386829 + j0.608804776800476 ohms/mile = Phase A neg seq Z
0.350329508807208 + j0.587556145614177 ohms/mile = Phase B neg seq Z
0.295803708805962 + j0.661533893295274 ohms/mile = Phase C neg seq Z
I’m out in the wilderness, so any wisdom will be appreciated!
Wild Alaska
Typical spacing on flat crossarms is phase A 0", phase B (middle) 26", and phase C 88". No transposing - i.e. phase B stays in the middle. For some sections they did periodically swap phase B from one side of the pole to the other, so then B would be 62" from A and 26" from C, and in the line sections where they did this the line becomes an untransposed (asymmetrical) REGULAR line (in which case the line may be treated as having phase B in the middle, thus simplifying the math somewhat, as A & C become symmetrical with respect to B).
Problem is, PTW, like almost ALL reference sources, assumes that asymmetrical lines are transposed, and even the SKM unbalanced module has no model for untransposed lines.
Review of basics: In an asymmetrical transmission line which has been TRANSPOSED, the three phases are periodically rotated into each position to average the effects of magnetic field cancellation (these unbalances show up as mutual reactances in the impedance matrices). Because of unequal magnetic field cancellation in an untransposed line, phase B has the lowest reactance, followed by whichever phase is closest to B (of course, in a regular untransposed line A & C will have the same reactance).
The standard assumption of a transposed line results in reactances composed of two components: Xa and Xd, where Xa is often called the reactance of the conductor out to 1' and only depends on the conductor's properties (GMR), and Xd is called the "spacing factor" and is the reactance from 1' out to the line separation. For transposed lines the line separation is the GMD = cube root of D1D2D3 (where the D are the line separations), and of course Xd is the same for all 3 phases.
So why not do as most engineers and just ignore the error? I'm tempted. After all, it's on the primary so its effect on the secondary is expected to be small. Well, in the past I would have. But we are now in the era of ARC-FLASH and sometimes either more (by causing extremely intense arcs) or less (by causing overcurrent devices to clear so slowly as to allow the arc to persist too long) AFC can increase the hazard to the point there is no PPE available. I've seen both cases occur ON THE SAME LOW VOLTAGE LINE: Stiff at the beginning, mushy at the end. So one can't always just make assumptions that cause more or less AFC; more accuracy than past practice required seems needed (the IEEE 85% assumption really doesn't help much). So my first question to answer: Is the overhead line asymmetry significant enough that it should not be ignored? I'm thinking if its effect is less than 5% I may ignore it.
Derive asymmetrical spacing factors for phase A case: I know the Ph.Ds go crazy analyzing these types of things, but I'm just a working engineer trying to come up with a model to correctly solve a problem. So using the great old Westinghouse T&D Ref Book, and starting from their derivation of Xd for transposed lines (Chap. 3, pp. 37-39), I derived the following pos & neg seq reactances:
ASSUMPTIONS:
1. Load impedance is balanced and >> line impedance, so that phase currents are approximately balanced and symmetrical.
2. Source voltage is balanced and symmetrical.
3. Line resistance = 0 (since inductance is geometric, we can add R back in later).
4. Ignore zero sequence because all transformers have line-to-line primaries, and arc-flash is only a concern at the low voltage level.
5. Other assumptions are from the Westinghouse text, pp. 34-39.
PHASE A POSITIVE SEQUENCE CASE (i.e. CW rotation):
From Eq 19, p. 37, and being careful to preserve the vector notation (which, for the transposed case, Westinghouse could omit), we have
(Eq1) Ea - E'a = Ia jXa - Ib jXd12 - Ic jXd13
where Xa = self-inductance out to 1' and Xd = spacing factor.
Then,
(Eq 2) ZA+ = jXA+ = (Ea - E'a)/Ia = jXa - (Ib Xd12)/Ia - (Ic Xd13)/Ia
Now, from assumption 1, and remembering that if the phase currents lag the phase voltages by an angle a, this angle a is subtracted out, we note that
- Ib/Ia = 1 @+60 and - Ic/Ia = 1 @-60, so Eq 2 reduces to
(Eq 3) XA+ = Xa + Xd12@+60 + Xd13@-60
Where XA+ is the positive sequence reactance of phase A. Note that where Xd = Xd12@+60 + Xd13@-60, non-zero IM{Xd} implies the existence of a negative or positive (phantom) resistance. Result looks unphysical because X is expected to be just a magnitude, but note that if Xd12 = Xd13 this reduces to the Westinghouse result for symmetrical or transposed lines. If correct, seems to imply the existence of a resistive element, even though the lines were assumed to have no resistance.
PHASE A NEGATIVE SEQUENCE CASE (CCW rotation):
For the negative sequence case, the angle of Vb- = 120 degrees, and the angle of Vc- = 240 degrees. From assumption 1, and once again remembering angle a, we have (note that here the Iabc are neg seq; for notational simplicity we just omitted the "-" from Ia-, etc.)
- Ib/Ia = 1 @ -60 and - Ic/Ia = 1 @ +60, so Eq 2 reduces to
(Eq 4) XA- = Xa + Xd12@-60 + Xd13@+60
Where XA- is the negative sequence reactance of phase A. Again, note that where Xd = Xd12@-60 + Xd13@+60, IM{Xd} implies the existence of a negative or positive (phantom) resistance.
QUESTIONS:
1. Has anyone calculated these things and determined if the asymmetry is significant with regard to arc-flash?
2. Above, I derived the reactances for the pos & neg sequence cases, but the PTW unbalanced module only appears to have an ABC domain Z matrix. Of course, as reactance is purely geometric, line resistance can be added back in at the end (see example below). Also Xa is available from reference books. The conversion from my results to the Z012 matrix, and then from the Z012 to Zabc matrix, looks difficult. Anyone have any slick ideas?
3. Any comments?
Actual line data for 397.5 ACSR, using the above derivation:
0.387133217613171 + j0.608804776800476 ohms/mile = Phase A pos seq Z
0.167670491192792 + j0.587556145614177 ohms/mile = Phase B pos seq Z
0.222196291194038 + j0.661533893295274 ohms/mile = Phase C pos seq Z
0.130866782386829 + j0.608804776800476 ohms/mile = Phase A neg seq Z
0.350329508807208 + j0.587556145614177 ohms/mile = Phase B neg seq Z
0.295803708805962 + j0.661533893295274 ohms/mile = Phase C neg seq Z
I’m out in the wilderness, so any wisdom will be appreciated!
Wild Alaska