Continue to Site

Eng-Tips is the largest engineering community on the Internet

Intelligent Work Forums for Engineering Professionals

  • Congratulations cowski on being selected by the Eng-Tips community for having the most helpful posts in the forums last week. Way to Go!

Understanding eurocodes and deflection. 2

Status
Not open for further replies.

cve60069

Civil/Environmental
May 1, 2010
84
Hello

I am in the process of 'converting' to the eurocodes, notably eurocode 5: Timber; and I am having trouble understanding the principles of deflection of a beam. I attended a seminar and have two books explaining the principles and each source describes the method differently with differing results.

Before eurocode, I would calculate the deflection for a udl as [bending = 5/384*(W.L^4)/E.I] + [creep = M.Kform/A.G] where Kform = 1.2 and G = E/16. The creep factor was for long-term effects.

The eurocode states simply that the instantaneous deflection is found for unfactored permanent and variable loads and each result multiplied by (1+kdef) and (1+'quasi-permanent factor'*kdef) respectfully to obtain the final deflection. The code makes no mention of what the instantaneous deflection is other than a mention of using mean values for elasticity and shear moduli.

I attended a seminar at TRADA and the lecturer calculated the instantaneous deflection for a udl as [5/384*(W.L^4)/E.I + M.Kform/A.G] for each of the unfactored permanent and variable actions; and then calculated the final deflections by multiplying the permanent action by (1+kdef) and the variable action by (1+'quasi-permanent factor'*kdef) and summing to get the final deflection. Please note that the lecturer included the creep factor [M.Kform/A.G] in his analysis.

I have two books at my disposal: 'Structural Timber Guide to Eurocode 5: Porteous and Kermani' and 'Manual for the design of timber building structures to Eurocode 5: Institute of Structural Engineers' and both books offer different advice.

The Structural Timber Guide to Eurocode 5 explains that kdef is a factor that takes into account creep and the factor increases the instantaneous deflection by 60%. The quasi-permanent-factor is normally 0.3 so the variable deflection is increased 18%. When I consider the book examples for a joists (page 150), the authors get bogged down in mathcad and it is very difficult to follow the logic, particulary when amplification factors are discussed which I associate with vibration. The authors do, however, include creep in the instantaneous deflection calculation.

The Manual for the design of timber building structures to Eurocode 5 gives less information but rewrites the formula in the eurocode so that creep is treated separately from the instantaneous deflection (page 22).

I am totally confused. To me, the instantaneous deflection is [5/384*(W.L^4)/E.I] and the final deflection includes the creep factor, whether it be [M.Kform/A.G] or (1+kdef) and (1+'quasi-permanent factor'*kdef); The creep factor should not be assessed at the instantaneous stage as it would be assessed twice.

Any advice or references would be very much appreciated.





 
Replies continue below

Recommended for you

Hello my friend! First of all check this article!
As you can see, M.Kform/A.G is not representing the creep deformations but the deflections due to shear. 5/384*(W.L^4)/E.I + M.Kform/A.G are both representing the instantaneous deflection. Then you have to use EN 1995-1-1 clause 7.2 in order to calculate the final deflections which include instantaneous + the long term / creep deformations!
 
Thank you for clearing up my doubts and thanks again for the eurocode link.

Regards
 
Status
Not open for further replies.

Part and Inventory Search

Sponsor