rsaeed
Mechanical
- May 20, 2010
- 18
Hi all
In UCS-79 the formula is
% extreme fibre elongation = 75t/Rf (1-Rf/Ro)
now i have an elliptical head 2:1 D=3500mm h=875mm K=1 and for corrosion case D=3506mm, h=878mm and K=.998
Now I cant figure out where do I get this Rf and Ro to find the percentage elongation which is comming out to be 9.255% when done by consultant using PVelite. I just want the same from the manual calcs.
Can anybody please explain this Rf and Ro?
Thanks in advance for this.
In UCS-79 the formula is
% extreme fibre elongation = 75t/Rf (1-Rf/Ro)
now i have an elliptical head 2:1 D=3500mm h=875mm K=1 and for corrosion case D=3506mm, h=878mm and K=.998
Now I cant figure out where do I get this Rf and Ro to find the percentage elongation which is comming out to be 9.255% when done by consultant using PVelite. I just want the same from the manual calcs.
Can anybody please explain this Rf and Ro?
Thanks in advance for this.