Continue to Site

Eng-Tips is the largest engineering community on the Internet

Intelligent Work Forums for Engineering Professionals

  • Congratulations The Obturator on being selected by the Eng-Tips community for having the most helpful posts in the forums last week. Way to Go!

Torsion in a cylinder with crack

Status
Not open for further replies.

YeamonKemp

Civil/Environmental
Mar 3, 2011
4
Hi,

I want to do an ANSYS analysis of a cylinder with a crack, subjected to torsion. I need to obtain the Stress intensity factor and simulate plastification.

I tried to simulate the load with MPC184 and a master-node with torsor moment. I also tried applying direct loads on the cover nodes, but in both cases the results were not good.


Which is the best way of simulating this case? Element type? How to apply loads?
 
Replies continue below

Recommended for you

Why weren't the results good? It would probably help if you provided more detail about what you tried (e.g., element types, material properties, orientation of crack, etc.).
 
I used Solid95 and MPC184 for connect the master-node.

I attach the macro. It contains other stuff in order to calculate the limit load, but the most important for me right now is the SIF.

The results are not good because they don't correspond with the ETM analytical solution...
 
 http://files.engineering.com/getfile.aspx?folder=c3ef001e-a631-495e-9d1a-2f97fdc1abd1&file=BFR0221_mpc.txt
i suspect there's an ANSY add-on to calc stress intensity (probably from a J-integral)

else use a handbook, like Rooke & Cartwright
 
There`s no problem to calculate SIF, with KCALC command. But I don't get good results. It might be because of the element type or how I generate the torsor moment. I suspect the stress is not well transmitted...

However, I can't use a handbook. The purpose is to simulate the SIF.
 
the way i read your input yield = 249MPa = 36ksi ... looks reasonable, but E = 3720 MPa = 0.5E6psi ... looks low

if you're got Al E = 10E6psi = 69GPa
 
The problem can't be there. I tried the same E (s-e) with a cracked prism and it worked perfectly.

Furthemore, the non-linear analysis is not necessary to calculate the Stress Intensity Factor.

Thanks anyway, I continue with my research...
 
Status
Not open for further replies.

Part and Inventory Search

Sponsor