BronYrAur
Mechanical
- Nov 2, 2005
- 799
It has been a little while since I studied my thermodymanics, so I need a little help here. Reducing steam pressure through a PRV is an isenthalpic process (no enthalpy change), correct? So If I have 100 psig (338 deg F) saturated steam and reduce it to 15 psi, what changes? I assume that I will have superheated steam at 15 psi, right? How can I determine what the temperature is?
Where I am going with this is that I currently have a steam to water heat exchanger being served by 15 psig steam. However, this 15 psig steam is coming immediately out of a PRV that reduces it from 100 psig. I want explore the possibility of just running a 15 psig main and not having to reduce the pressure, but a saturated 15 psig main is only about 250 deg F. I assume that I have a higher temperature steam now, but how high? Is that even inportant in the grand scheme of heat transfer, since I know that the latent heat is the driving force - at least I think it is.
Any thoughts?
Where I am going with this is that I currently have a steam to water heat exchanger being served by 15 psig steam. However, this 15 psig steam is coming immediately out of a PRV that reduces it from 100 psig. I want explore the possibility of just running a 15 psig main and not having to reduce the pressure, but a saturated 15 psig main is only about 250 deg F. I assume that I have a higher temperature steam now, but how high? Is that even inportant in the grand scheme of heat transfer, since I know that the latent heat is the driving force - at least I think it is.
Any thoughts?