I agree with skogsgurra in general an occasional 160 / 148 = 8% overload of a 50hp motor is not likely to be a problem in itself.
It is more important to understand the duty cycle and effects of repeated starting.
I believe there are some significant shortfallings in the link posted above
Look at the first example of rms current calculation that they provided:
Starting or acceleration current = 10 A for 0.2 sec
Operational or running current = 1.5 A for 0.1 sec
Deceleration current = 8.5 A for 0.2 sec
Idle time = 0.8 sec
They calculate an RMS current of 5.16A based on the entire interval 0.1+0.1+0.2+0.8 seconds. This is the effective current used as the basis for thermal evaluation.
I1 = sqrt((10^2*0.2 +1.5^2*0.1 +8.5^2*0.2)/(0.2+0.1+0.2+0.8))=5.16
The logic for this approach is as UKPete explained that the average power input is related to the rms current and presumably this is a good enough approximation if the motor time constant is longer than the duty cycle.
Ordinarily I agree with that approach IF we are talking about a motor running under varying loads but always running. In the particular example posted in the link, the motor is NOT running thoughout the duty cycle but in fact idle more than 50% of the time! We have taken credit for the reduced (0) heat input during this idel period but we have not penalized for the reduced cooling during the period when the motor is idle. It amounts to an assumption that the idle motor dissipates as much heat (for given deltaT) as a running motor. It is a very lopsided calculation and a very dubious non-conservative result.
To envelope the true equivalent heating current we can do the above non-conservative calculation I1 over the whole cycle 0.1+0.1+0.2+0.8 seconds..... AND an additional overly conservative calculation I2 over the running period only while running. This overly -conservative calculaiton equates to an assumption that no heat is added or dissipated during the idle period which is overly conservative (there is some heat dissipated).
The conservative calculation:
I2 = +sqrt((10^2*0.2 +1.5^2*0.1 +8.5^2*0.2)/(0.2+0.1+0.2)) =8.3
Actual rms current for calculation of effective heating would lie somewhere in between
I1 < Ieffective < I2
5.16 < Ieffective < 8.3
Another laughable thing about the link is their treatment of thermal time constant.
Thermal time constant is the prodcut of specific heat capacity and thermal resistance. Comparing the running and idle conditions, the heat capacity is the same but thermal resistance is an order of magnitude higher during idle conditions than during running conditions..... therefore thermal time constant is an order of magnitude higher for idel conditions than running conditions. But if you look at the calculation they use the same time constant for both idle and runnning conditions!
Sorry, I am not meaning to be picky. Any calculation has assumptions, simplifications and weaknesses which can be improved. This particular link is definitely one of them.
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