Jul 17, 2003 #1 woodrow Mechanical Joined Aug 21, 2001 Messages 3 Location US Can anyone tell me what the specific heat of the following mixture would be? 40% Water 40% Ethylene Glycol 20% Methanol
Can anyone tell me what the specific heat of the following mixture would be? 40% Water 40% Ethylene Glycol 20% Methanol
Jul 17, 2003 #2 SeanB Chemical Joined Jun 11, 2003 Messages 258 Location CA From Hysys - specific heat = 112.38 kJ/kgmole C Upvote 0 Downvote
Jul 17, 2003 Thread starter #3 woodrow Mechanical Joined Aug 21, 2001 Messages 3 Location US Thanks SeanB! Out of curiosity, how did you come up with that value? Upvote 0 Downvote
Jul 17, 2003 #4 SeanB Chemical Joined Jun 11, 2003 Messages 258 Location CA I just ran a simulation in Hysys, using a basis of 1 kgmole/hr for flow and standard conditions ie 15 deg C and 101.3 kPa. Upvote 0 Downvote
I just ran a simulation in Hysys, using a basis of 1 kgmole/hr for flow and standard conditions ie 15 deg C and 101.3 kPa.
Jul 18, 2003 Thread starter #5 woodrow Mechanical Joined Aug 21, 2001 Messages 3 Location US Thanks! Upvote 0 Downvote
Jul 18, 2003 #6 CHD01 Mechanical Joined Jul 2, 2002 Messages 252 Location US The specific heat of a mixture is simply equal to the sum of the s[ecific heats for each component x the volume fraction for each component. The more you learn, the less you are certain of. Upvote 0 Downvote
The specific heat of a mixture is simply equal to the sum of the s[ecific heats for each component x the volume fraction for each component. The more you learn, the less you are certain of.