vonsteimel
Mechanical
- Oct 19, 2010
- 132
Greetings,
I'm a mechanical guy so I wanted to make sure I'm understanding this right.
We are going to start using tablets as scanning stations to record job costing, inventory.etc (why tablets? I don't know, not my decision....)
Anyway, there will be quite a number of them which will never go to sleep. So I was having a look at the power consumption and was a little taken back by the inefficiency of what I found.
The DC converter/charger reads:
INPUT: 100-240V 0.3A
OUTPUT:5.35V 2A
So if the wall is 110V, then 110V X 0.3A = 33W "sucked from the wall" (the number used to figure the cost of powering the tablet)
When only 5.35V X 2A = 10.7W actually used by the tablet...? That's a 68% loss !?
Is this correct? I know the converter puts off heat but I didn't figure it was this much.
Thanks,
VS
I'm a mechanical guy so I wanted to make sure I'm understanding this right.
We are going to start using tablets as scanning stations to record job costing, inventory.etc (why tablets? I don't know, not my decision....)
Anyway, there will be quite a number of them which will never go to sleep. So I was having a look at the power consumption and was a little taken back by the inefficiency of what I found.
The DC converter/charger reads:
INPUT: 100-240V 0.3A
OUTPUT:5.35V 2A
So if the wall is 110V, then 110V X 0.3A = 33W "sucked from the wall" (the number used to figure the cost of powering the tablet)
When only 5.35V X 2A = 10.7W actually used by the tablet...? That's a 68% loss !?
Is this correct? I know the converter puts off heat but I didn't figure it was this much.
Thanks,
VS