Thanks a lot for your replies. I have read the web pages you mentioned, but all they do is just trial and error as I. Do somebody make a formal electrical calculus of the circuit by result of connecting the capacitor (I mean angles phases, formula for the capacitor value)??. It is supposed that if I change from one to another capacitor the angles phases and by the way the current changes very much??. One the things they said is that is better to use an IDLER motor, by the way what is that??, is only another motor?, it is not coupled, isn't it???, it is only used as a generator?. I prefer not to use another motor, but I don't know, in my experiments my motor runs well (without load), but with load things changes...one of the lines, the direct one, "pulls" much more current (2x) than the others (the other direct and the third leg). My pump (coupled directly with the motor) works but the current is 2x the nominal current, so it a matter of time for my motor to "die", also I don´t know if it is going to be useful for my application, but I have to solve it.
For TECO, this motor is an A2Q motor (from WEG), is it used coupled directly with a water pump, they work both summerged so we obtain more power from the motor due to the water cooling. The data (for normal 3phase supply) you require is the following:
Power 2 HP (1,47 Kw), but we obtain almost 2 Kw
Two poles 60Hz 220V 3500rpm Double triangle conection
Cp/Cn 3
Cm/Cn 2.8
Ip/In 6.6
Thanks in advance