drdherl
Mechanical
- Sep 4, 2008
- 11
I have an assembly of parts with defined size tolerances.
Parts stack on top of one another. I must assume that tolerances for each part would fit within normal distribution.
When I calculate, RSS, (taking the square root of the sum of the tolerances -->
1.00 +/- .002
.500 +/- .003
.75 +/- .004
.500 +/- .005
.600 +/- .003
(.002^2 + .003^2 + .004^2 + .005^2 + .003^2)^.5 = .0079
Given above, is it reasonably safe to say that 99.7% of time part thickness will fall within 3.342 and 3.358
more simpler...does RSS equate roughly to 3 sigma?
For some reason, I thought the RSS was equal to 1 sigma equal to standard deviation but I think I've been wrong.
Parts stack on top of one another. I must assume that tolerances for each part would fit within normal distribution.
When I calculate, RSS, (taking the square root of the sum of the tolerances -->
1.00 +/- .002
.500 +/- .003
.75 +/- .004
.500 +/- .005
.600 +/- .003
(.002^2 + .003^2 + .004^2 + .005^2 + .003^2)^.5 = .0079
Given above, is it reasonably safe to say that 99.7% of time part thickness will fall within 3.342 and 3.358
more simpler...does RSS equate roughly to 3 sigma?
For some reason, I thought the RSS was equal to 1 sigma equal to standard deviation but I think I've been wrong.