notnats
Mechanical
- Apr 25, 2003
- 179
Here is a paradox that automotive engineers can solve for me.
Because a tyre is slightly flattened at the point of contact with the road, the height of the axle above the road is less than the radius of the tyre.
The driving torque of the axle produces a forward force at the point of contact of T/r, where r is the height of the axle above the road. OK.
But when the wheel turns a full 360 degrees, the distance the vehicle moves is 2piR where R is the unloaded radius of the tyre. While the wheel is rotating, the effective force would appear to be T/R.
Is the driving force greater when the vehicle is stationary than when moving?
If not, what happens to the extra rubber in the circumference?
I realise this is trivial, but I have worried about this now for some years, (not very hard though)
Jeff
Because a tyre is slightly flattened at the point of contact with the road, the height of the axle above the road is less than the radius of the tyre.
The driving torque of the axle produces a forward force at the point of contact of T/r, where r is the height of the axle above the road. OK.
But when the wheel turns a full 360 degrees, the distance the vehicle moves is 2piR where R is the unloaded radius of the tyre. While the wheel is rotating, the effective force would appear to be T/R.
Is the driving force greater when the vehicle is stationary than when moving?
If not, what happens to the extra rubber in the circumference?
I realise this is trivial, but I have worried about this now for some years, (not very hard though)
Jeff