Eng.Edward.M
Electrical
- Mar 5, 2021
- 13
Good morning everyone!
I have a doubt about how the adjustment is made in the RSAS 3750 relay.
Example: TC - 500/5
Ip - timed starting current
scale 1 - 2
steps 0.2
With this I can adjust the KpA / KpB / Kpc to 1/1.2/1.4/1.6/1.8/2
We have the equation Ip = Kp x In
Therefore, if I select 1.2, the result will be Ip = 1.2 x 5 x 100(RTC) = 600A
Ii - instantaneous inrush current
scale 1 - 5
steps 1
C = 4
With this I can adjust the Ki to 1/2/3/4/5
We have the equation Ii=Ki x C x Ip
So, if I select 2, the result will be Ii= 2 x 4 x Ip(1.2 x 5) x 100(RTC) = 4800A
I have a doubt about how the adjustment is made in the RSAS 3750 relay.
Example: TC - 500/5
Ip - timed starting current
scale 1 - 2
steps 0.2
With this I can adjust the KpA / KpB / Kpc to 1/1.2/1.4/1.6/1.8/2
We have the equation Ip = Kp x In
Therefore, if I select 1.2, the result will be Ip = 1.2 x 5 x 100(RTC) = 600A
Ii - instantaneous inrush current
scale 1 - 5
steps 1
C = 4
With this I can adjust the Ki to 1/2/3/4/5
We have the equation Ii=Ki x C x Ip
So, if I select 2, the result will be Ii= 2 x 4 x Ip(1.2 x 5) x 100(RTC) = 4800A