Nov 19, 2009 #1 subbaraao Mechanical Joined Oct 14, 2009 Messages 8 Location IN Can any one tell me the relation between pump capacity,head & power. We have a pump of capacity 125cumph head 50 meters motor 37kw&rpm 2900. If we reduce rpm to 1440 what would be the capacity,head&motor power required
Can any one tell me the relation between pump capacity,head & power. We have a pump of capacity 125cumph head 50 meters motor 37kw&rpm 2900. If we reduce rpm to 1440 what would be the capacity,head&motor power required
Nov 19, 2009 #2 A Artisi Mechanical Joined Jun 11, 2003 Messages 6,581 Location AU Q (flow) changes as the ratio of speed Head changes as the square of the speed change Power changes as the cube of the speed change Q = N1/N2. Flow will be 62.5 cumph Head = (N1 /N2)^2. Head will be 12.5 metres Power = (N1 / N2)^3. Power will be 4.625Kw Upvote 0 Downvote
Q (flow) changes as the ratio of speed Head changes as the square of the speed change Power changes as the cube of the speed change Q = N1/N2. Flow will be 62.5 cumph Head = (N1 /N2)^2. Head will be 12.5 metres Power = (N1 / N2)^3. Power will be 4.625Kw
Nov 20, 2009 #3 SNORGY Mechanical Joined Sep 14, 2005 Messages 2,510 Location CA At an apparent pump efficiency of 46%... Regards, SNORGY. Upvote 0 Downvote