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Piezo Element Energy 2

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swertel

Mechanical
Dec 21, 2000
2,067
Please help out a mechanical engineer interpret this electrical verbiage.

I have an assembly that uses a Piezo element in it to excite a component upon impact. The specification requires that it
shall supply electrical energy equivalent to that discharged by a 0.005 microfarad capacitor that has been charged to 9 volts, minimum, when impacted by a 1.94 ounce steel ball dropped from a height of no greater than two inches (2”)

What is that in terms of Voltage, Amps, or Watts?

The disc is .7 inch diameter by .1 inch thick per MIL-P-12815 if that helps.

I'm trying to test the component that gets energized by the piezo without destroying a bunch of piezo elements in the process. Thus, I need to know how much energy the piezo actually gives off so I can reproduce it using another supply source.

--Scott
 
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Well, a 0.005uF capacitor charged to 9 volts, W=1/2*C*V^2, or energy equivalent to 0.405 micro-coulombs. One coulomb is 1 watt-second.

A piezo under flexing may produce a voltage greater than 9 volts. A 1.94 oz steel ball hitting a piezo from 2" will produce a transient voltage of very short duration. Normally a piezo being struck will produce a voltage of one polarity as it is struck, and reverse polarity as it relaxes back to it's original position, but in this case the piezo will produce a voltage until it fractures.

If I was to non-destructively duplicate the condition, I would first verify the spec by setting-up the piezo with the circuit and an oscilloscope, perform the steel ball drop and record the waveform, look at the voltage/time given the circuit impedance - just to make sure I'm duplicating reasonably the 0.405 micro-couloumb value. -THEN- I would use the waveform I recorded, and play it back through a arbitrary waveform generator (taking into account possible differences in source impedance of a piezo vs the generator) to duplicate the conditions to check the operation of the circuits.





 
Hey Comco, I think you skipped the divide by two. Also, I think you mean joules rather than coulombs. I come up with 2.025E-7 joules.

Glenn
 
Jiminy!! ;-) A coulomb is an amp-second


I also get 202.5 nJ of energy.

One might hope that the specification has a more direct meaning; that the discharge of a 9V impression on a 5 nF capacitor actually behaves like the piezo element:

Based on that webpage, one might just try to see if a 5 nF cap with 9 V behaves like the piezo element.

TTFN

FAQ731-376
 
DOH!!

Your right geekEE. That's what I get for replying at the end of the work day when my brain is half fried.
 
Thanks, Comco for the detailed explanation. And thanks, Glenn, for the errata. I'd thank IRstuff, but I have other dealings with him online and he needs no applause.

--Scott
 
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