Path results - radial displacement

[arnoldh]

Dear Ansys users

when I want to get the path results from a straight edge in WB, I use the code snippet

/POST1
/show,png
/gfile,650
/RGB,INDEX,100,100,100,0
/RGB,INDEX,0,0,0,15

PATH,straigth,2,6,20

PPATH,1,,41.275,41.275,52.387,
PPATH,2,,41.275,41.275,68.263,

PDEF,straigth,U,X,
PCALC,DERI,dstraigth,straigth,S,1,1,

PLPATH,zyl
PLPATH,dzyl
PAGET,PathData,TABLE
*CREATE,ansuitmp
*CFOPEN,'C:\temp\straigth','txt',' '
*VWRITE,'point','x','y','z','s','zyl','dzyl'
(A5,' ',A12,' ',A12,' ',A12,' ',A12,' ',A12,' ',A12)
*VWRITE,SEQU,PathData(1,1,1),PathData(1,2,1),PathData(1,3,1),PathData(1,4,1),PathData(1,5,1),PathData(1,6,1)
(F5.0,' ',E12.6,' ',E12.6,' ',E12.6,' ',E12.6,' ',E12.6,' ',E12.6)
*CFCLOS
*END
/INPUT,ansuitmp

I would like to change the snippet, so I can use it for a curved edge (a quarter cylinder edge) by defining two points, and then determine the radial deformation. The cylindrical CS for the radial displacement is CS 52 (which lies in the centre of the cylinder). Can anybody tell me how I have to modify this APDL code to get the radial results?

Regards,

Arnold