JoshH726
Structural
- Aug 3, 2010
- 83
If I have a pedestal (54"x28"x72" tall), Ag=1512 in^2, and the cross-section is larger than required for the loads, so 318 10.8.4 will allow you to reduce the Ag by 1/2, or 756in^2. Is 1/2Ag (756 in^2) then used for 15.8.2: 0.005Ag requirements, so 1/2*0.005*Ag=1.89 in^2 (min. reinforcement then controls), or do you still use 0.005Ag = 3.78 in^2? It seems counter-intuitive that 10.8.4 allows you to reduce the Ag, which you seem to be able to use for 10.9, but you can't use it for 15.8.2.