Little Inch,
You state use Sa as listed in table A-1, I suppose you mean Sh as per §302.3.5(c) or just plane old S per §302.3.1 . Sa is a combination of Sc, Sh and Sl as per §302.3.5(d).
I know ASMEVIII is a pressure vessel code but it is the design by analysis section (=§5) I'm referring to, so when choosing FEM you will end up using it's rules.
In some cases the biggest bending stresses are due to the lifting operation other bending stresses are from dead load. The case I'm keen to receive your reply is when the dead load stresses are minimal compared to the lifting stresses.
I'm also well aware of the fact that buckling etc requires verification if above yield.
Big Inch,
Sa=f*(1.25*(Sc+Sh)-SL))
- Suppose no meaningful temperature difference => Sc=Sh
- Suppose SL is minimal (near zero).
- Suppose f=1 but can also be 1,2 according fig. 302.3.5.
As already stated S=min(Sy/1.5;UTS/3), so lets suppose the Sy value determines the allowable stress.
Sa=1,2*(1,25*((Sy/1,5) +(Sy/1,5))-0)=2*Sy.
So thank you very much for your refreshing input which helped me to solve at least one of my questions.
Before being verbally attacked, I agree it just doesn't feel right, but is there any real argument why it should never go above the SMYS.
Consider a piping system where due to thermal loadings (the impossible happens) and the stress value goes above the yield. Local yielding occur and stresses drop. A little later the product is redirected causing the piping temperature to drop and so does the thermal stresses. Is it not somewhat similar. Thermal stresses are secondary but so is imposed displacement...
I just keep on trying