PrescottEngineer
Structural
- Jun 3, 2010
- 20
I want to attach a wood beam to a wood column using a lag screw with 12" embedment into the column, not including the length of the tapered tip. I am expecting the lag screw to resist withdrawal only. The beam is a 6×12 DF #1 and the column is a 6×6 DF #1. The lag screw conforms to A307 grade A, Fy=60,000psi, and has a standard washer conforming to ASTM F844. Based on the table below, I find compression perpendicular to grain in the wood beam is the limiting factor by far.
1/2"Ø 3/4"Ø
Tensile Capacity 3883 lbs 9460 lbs
12" Embed Capacity 3402 lbs 4617 lbs
Comp Perp to Grain Capacity 966 lbs 1951 lbs
If I use a round plate washer from Portland Bolt instead of a standard washer, then I get the following values.
1/2"Ø 3/4"Ø
Comp Perp to Grain Capacity 2772 lbs 4626 lbs
So my question is, is everyone using large plate washers on lag screws or am I missing something? Thanks in advance for all your help.
Additional calculations are below.
Max Capacity of a lag screw at the net (root) section
1/2"Ø - Dr = 0.371" [2005 NDS Appendix L] = (60,000 psi * pi * (0.371"/2)^2)/1.67 = 3883 lbs [Steel Manual, 13th edition, Page 5-2]
3/4" - Dr = 0.579" [2005 NDS Appendix L] = (60,000 psi * pi * (0.579"/2)^2)/1.67 = 9460 lbs [Steel Manual, 13th edition, Page 5-2]
Capacity of a lag screw with 12" embedment
1/2"Ø - 378 lbs/in * 12" * 0.75 (Ceg) = 3402 lbs [2005 NDS Page 68]
3/4"Ø - 513 lbs/in * 12" * 0.75 (Ceg) = 4617 lbs [2005 NDS Page 68]
Compression Perpendicular to grain with a standard washer conforming to ASTM F844
1/2"Ø - 1 3/8"Ø OD and 9/16"Ø ID - 625 psi * pi * ((1.375"/2)^2-(0.5625"/2)^2) * 1.25 (Cb) = 966 lbs [2005 NDS Supplement Page 45] and [2005 NDS Page 68]
3/4"Ø - 2"Ø OD and 13/16"Ø ID - 625 psi * pi * ((2"/2)^2-(0.8125"/2)^2) * 1.19 (Cb) = 1951 lbs [2005 NDS Supplement Page 45] and [2005 NDS Page 68]
Compression Perpendicular to grain with a round plate washer from Portland Bolt
1/2"Ø - 2 1/4"Ø OD and 9/16"Ø ID - 625 psi * pi * ((2.25"/2)^2-(0.5625"/2)^2) * 1.19 (Cb) = 2772 lbs [2005 NDS Supplement Page 45] and [2005 NDS Page 68]
3/4"Ø - 3"Ø OD and 13/16"Ø ID - 625 psi * pi * ((3"/2)^2-(0.8125"/2)^2) * 1.13 (Cb) = 4626 lbs [2005 NDS Supplement Page 45] and [2005 NDS Page 68]
1/2"Ø 3/4"Ø
Tensile Capacity 3883 lbs 9460 lbs
12" Embed Capacity 3402 lbs 4617 lbs
Comp Perp to Grain Capacity 966 lbs 1951 lbs
If I use a round plate washer from Portland Bolt instead of a standard washer, then I get the following values.
1/2"Ø 3/4"Ø
Comp Perp to Grain Capacity 2772 lbs 4626 lbs
So my question is, is everyone using large plate washers on lag screws or am I missing something? Thanks in advance for all your help.
Additional calculations are below.
Max Capacity of a lag screw at the net (root) section
1/2"Ø - Dr = 0.371" [2005 NDS Appendix L] = (60,000 psi * pi * (0.371"/2)^2)/1.67 = 3883 lbs [Steel Manual, 13th edition, Page 5-2]
3/4" - Dr = 0.579" [2005 NDS Appendix L] = (60,000 psi * pi * (0.579"/2)^2)/1.67 = 9460 lbs [Steel Manual, 13th edition, Page 5-2]
Capacity of a lag screw with 12" embedment
1/2"Ø - 378 lbs/in * 12" * 0.75 (Ceg) = 3402 lbs [2005 NDS Page 68]
3/4"Ø - 513 lbs/in * 12" * 0.75 (Ceg) = 4617 lbs [2005 NDS Page 68]
Compression Perpendicular to grain with a standard washer conforming to ASTM F844
1/2"Ø - 1 3/8"Ø OD and 9/16"Ø ID - 625 psi * pi * ((1.375"/2)^2-(0.5625"/2)^2) * 1.25 (Cb) = 966 lbs [2005 NDS Supplement Page 45] and [2005 NDS Page 68]
3/4"Ø - 2"Ø OD and 13/16"Ø ID - 625 psi * pi * ((2"/2)^2-(0.8125"/2)^2) * 1.19 (Cb) = 1951 lbs [2005 NDS Supplement Page 45] and [2005 NDS Page 68]
Compression Perpendicular to grain with a round plate washer from Portland Bolt
1/2"Ø - 2 1/4"Ø OD and 9/16"Ø ID - 625 psi * pi * ((2.25"/2)^2-(0.5625"/2)^2) * 1.19 (Cb) = 2772 lbs [2005 NDS Supplement Page 45] and [2005 NDS Page 68]
3/4"Ø - 3"Ø OD and 13/16"Ø ID - 625 psi * pi * ((3"/2)^2-(0.8125"/2)^2) * 1.13 (Cb) = 4626 lbs [2005 NDS Supplement Page 45] and [2005 NDS Page 68]