I am trying to find this formula in the ACI 318-14 code: Phi Mn=phi*rho*fy*(b*d^2)*(1-rho*fy/1.7f'c) 1

[Iasonasx]

I am trying to find this formula in the ACI 318-14 code: ΦMn=φ*ρ*fy*(b*d^2)*(1-ρ*fy/1.7f'c). Could somebody please let me know if it is given in any other form somewhere?
Thanks

 

[saadpervez1]

This formula is derived from Mn = As*fy*(d-a/2)

Where As = p*b*d and
a = As*fy/(0.85*f'c*b)

 

[Iasonasx]

Thank you!