In order for a motor to turn 540rpm with 15.6gpm input it needs to have a displacement of 15.6*231/540 = 6.67 cu.in./rev
That torque that size motor will deliver at 3300psi is 6.67*33000/(2*pi) = 35,032 lb.-in. or 2,919 lb.-ft.
Can you find a motor that size or close to that?
Will the torque be enough, too much, too little? Snow load on the blower will determine torque demand, and directly pressure demand. As the snow load varies so will the hydraulic pressure.
Will your prime mover, gas or diesel engine, deliver what the pump will demand? Will the engine speed be controlled by a governor or fixed throttle opening? Where on the torque curve will your engine be operating at the speed required to have the pump produce 15.6gpm? If too low on the torque curve the engine will slow and stall.
Ted