The reaction is
NaH(c) + H2O(l) --> NaOH(aq) + H2(g)
The actual amount of heat increases with the amount of water available to dissolve the NaOH, but the dilution would temper any temperature rise. The &[ignore]Delta[/ignore];HRxn below uses the value for NaOH(aq, 400 H2O):
&[ignore]Delta[/ignore];HRxn, 25 C = -112 + 0 –(-14) –(-68) = -30 kcal/mol
Data are from Perry’s, 7th ed.