mfadzil
Mechanical
- May 18, 2008
- 20
Hi all,
I have questions, is there any guideline on positioning vibration isolators beneath a generator set skid?
Lets say the generator package weight is 65mT, so I place 10 points of vibration spring. How to positioning the vibration isolator?
Can anyone guide me the formula to calculate the reaction of the isolator point?
"As the generator has 10 points of isolator, so I did divided it to 4 portion to get Ra, Rb, Rc, Rd and Re. For example;
Ra = P1b1/L1 -----1
Rb1 = P1a/L1 ------2
--------------------
Rb2 = P2c1/L2 -----3
Rc1 = P2b2/L2 -----4
--------------------
Rc2 = P3d1/L3 -----5
Rd1 = P3c2/L3 -----6
--------------------
Rd2 = P4e/L4 ------7
Re = P4d2/L4 -----8
--------------------
Ra + (Rb1+Rb2) + (Rc1+Rc2) + (Rd1+Rd2) + Re = 0
Ra, Rb1, Rb2.. is the reaction, P1, P2, P3.. is the forces.
a,b1,b2.. is the position of P1,P2,P3.. from Ra,Rb2,Rc2..
L1,L2.. is the length of Ra to Rb1, Rb2 to Rc1.."
After completing the calculation, I've divide each reaction to two to get all 10 points of reaction.
See attachment for the load and reaction.
If I'm wrong, please correct me and if you have any better idea, please share it with me. All the forces, P in the diagram are pre-calculated and is cumulative as the c.o.g shall be between each reaction, R.
Thank you.
I have questions, is there any guideline on positioning vibration isolators beneath a generator set skid?
Lets say the generator package weight is 65mT, so I place 10 points of vibration spring. How to positioning the vibration isolator?
Can anyone guide me the formula to calculate the reaction of the isolator point?
"As the generator has 10 points of isolator, so I did divided it to 4 portion to get Ra, Rb, Rc, Rd and Re. For example;
Ra = P1b1/L1 -----1
Rb1 = P1a/L1 ------2
--------------------
Rb2 = P2c1/L2 -----3
Rc1 = P2b2/L2 -----4
--------------------
Rc2 = P3d1/L3 -----5
Rd1 = P3c2/L3 -----6
--------------------
Rd2 = P4e/L4 ------7
Re = P4d2/L4 -----8
--------------------
Ra + (Rb1+Rb2) + (Rc1+Rc2) + (Rd1+Rd2) + Re = 0
Ra, Rb1, Rb2.. is the reaction, P1, P2, P3.. is the forces.
a,b1,b2.. is the position of P1,P2,P3.. from Ra,Rb2,Rc2..
L1,L2.. is the length of Ra to Rb1, Rb2 to Rc1.."
After completing the calculation, I've divide each reaction to two to get all 10 points of reaction.
See attachment for the load and reaction.
If I'm wrong, please correct me and if you have any better idea, please share it with me. All the forces, P in the diagram are pre-calculated and is cumulative as the c.o.g shall be between each reaction, R.
Thank you.