Hey,thank you first for your helpful answer
So to determine the amount of heat I need to remove I am confused between 2 methods and I do not know which one is correct
first method
The Heat lost Q (J) by the cylinder when its temperature decreases from Ti = 400 °C to Tf= 100 °C is:
Q= mc∆T = m c (Ti-Tf)
Where
[ul]
[li]m is the mass of the roll Kg[/li]
[li]c is the Specific heat of cast iron roll J/kg K[/li]
[li]T
i Initial temperature of the cylinder[/li]
[li]T
f Final temperature of the cylinder[/li]
[/ul]
and I divide the amount heat Q by the contact time and I replace it in the equation (*)
second one
the hate rate flow is given by
Q⁄t=hA(Tf-Ts)
[ul]
[li]h heat transfer coefficient, W/(m
2•K)[/li]
[li]A surface area where the heat transfer takes place, m
2[/li]
[li]T
f temperature of the surrounding fluid[/li]
[li]T
s temperature of the solid surface[/li]
--------------
once the heat to be evacuated is calculated I will pass to the determination of the flow rate of cooling water whose calculation is done as follows
The volumetric flow rate in a heating system can be expressed as
Dv=(Q⁄t)/(ρ cp ∆T) (*)
Where
[li]D
v = volumetric flow rate (m
3/s)[/li]
[li]Q⁄t = heat flow rate (J/s, W)[/li]
[li]cp = water specific heat (J/kg°C)[/li]
[li]ρ = water density (kg/m
3)[/li]
[li]∆T=T
f-T
i = temperature difference (°C)[/li]
water's Initial temperature T
i
waterer's Final temperature T
f
[/ul]
except that for this 2nd stage I do not know the temperature that the water will have after the heat exchange
Thank you !