Hello,
If frequency of rotation of the gears is N, and if v represents the total volume of liquid displaced from each gear wheel during one revolution, then capacity is given by:
Q = 2vN (1)
From geometric considerations, it is seen that the displaced volume, v, is given approximately by:
v = Pi/4[DSq.- DoSq.]x W = Pi x DSq. x W [1-(Do/D)Sq.] (2)
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4
where: DSq. = Outside gear diameter in. (squared)
DoSq. = Pitch Dia. of gear in. (squared)
W = Width of gear in.
Equations (1) and (2) yield:
Q = a N (3)
where: a = Pi x DSq. x W [1-(Do/D)Sq.] (4)
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2
where: Q = Volumetric flowrate in cubic inches/second
a = Capacity of gear pump, cubic inches/revolution
I hope I have this right, please let me know how this works.
PS, v = Volume in cubic inches, N = rpm
In equation (2) Pi, DSQ. and W are all divided by 4, also, in equation (4) the three are divided by 2.