Tek-Tips is the largest IT community on the Internet today!

Members share and learn making Tek-Tips Forums the best source of peer-reviewed technical information on the Internet!

  • Congratulations TugboatEng on being selected by the Eng-Tips community for having the most helpful posts in the forums last week. Way to Go!

FORMULA TO CALCULATE DIAMETER OF BUNCHED ELECTRICAL CORES

Status
Not open for further replies.

DFOUR

Electrical
Joined
Aug 11, 2003
Messages
1
Location
AU
CAN ANYONE HELP WE ARE LOOKING FOR A FORMULA TO CALCULATE
THE BUNCHED DIAMETER OF 1 TO 30 CORES OF ELECTRICAL WIRE.

THANKS

 
For cables of the same diameter
There is a factor
1 cable Factor is 1
7 cables the factor is 3
19 cables the factor is 5
37 cables the factor is 7
61 cables the factor is 9
Cables all of the same diameter, formed around a central single core follow the "rule of 6"
the first layer is 6 plus the inner core is 7 (the 7 wire assembly is 3 cable diameters in diameter)

the second layer contains 6+6 plus the 7 below it, so it has 19 total cables and is 5 cable diameters in diameter.

The third layer is 6+6+6 or 18 cables plus 19.... and so on

hopes this helps

Wilber
 
If all the strands are the same diameter it is very simple.

D = d*(2*LAYERS-1)
with d the strand diameter & LAYERS the number of strand layers. Typically the number of strands N equals
N = 1+3*LAYERS^2-3*LAYERS.

For example a N=37 strand cable with d=.1466" has
LAYERS = 4 because 37=1+3*4^2-3*4, and
D = .1466*(2*4-1) = 1.0262" the outter dia of the cable.

John Alexiou
Alcoa - SAG10/Vibrec Development.
john.alexiou@alcoa.com
 
Status
Not open for further replies.

Part and Inventory Search

Sponsor

Back
Top