Feeder current

[pintodacosta]

Hi,

I have a 3 electrical boards (3phase 380/230) to feed from a substation.

Electrical Board 1:
S=46KVA
Electrical Board 2:
S=46KVA
Electrical Board 3:
S=120KVA

The current that each eletrical board will "consume" is calculated by:

I = S/(sqrt 3 *400)

Is this correct?

 

[davidbeach]

Where'd the 400 come from?

 

[waross]

380/230V does not equate.
Possibly 400/230V?????

Bill
--------------------
"Why not the best?"
Jimmy Carter

 

[pintodacosta]

Hi,

The voltage level is 230/400.

it comes from a feeder located in a private substation.

rgds

 

[waross]

(KVA x 1000) / (400V x 1.73) = A
(KVA x 1000) / (230V x 3) = A

Bill
--------------------
"Why not the best?"
Jimmy Carter

 

[pintodacosta]

Tx to all for the support