bdruehl:
You better not have a roller for a reaction at the back span, or you have an unstable col. in the direction of the length of the beam. That reaction better be tied down for uplift and prevented from moving in the direction of the length of the beam. I think I understand your concern though, you think that as the canti. flexes (its curvature), you will get an “e” approx. equal to (col. dim./2) toward the tip of the canti. as the outer edge of the col. is loaded by the bending beam.
Is this a public balcony with a LL of 100psf, or a residential deck with 40psf +, and a couple feet, right out at the railing, at 60psf? How do you know the size and stress grade of the col.? What is the load path at its base, a 44kip col. load is fairly sizable. I would reconsider a col. which couldn’t take a 1" eccentricity.
BAretired has it right in his posts 2MAR 15:44 & 19:08. As an approx. I would use a triangular loading to rep. the beam curvature. Thus, the resultant might fall at (d/2)(2/3) = d/3 from the center of the col. However, I think the bearing triangle would start inboard of the col. center so I’ll say maybe e = d/4. This would induce an eccentricity, and moment at the top of the col. but not much curvature at that point in the col., since I think you would just get some crushing of the wood parallel to the grain.
Why don’t you nail a 1" thick plate to the top of the col., same size a col., and watch nailing edge dist. Then weld a 3/4" square bar to the top/center of the pl./col., now e = 3/8", approx. zero. Now check web crippling on the stl. bm. And, I still don’t like a col. designed that close to its limit when I don’t know its condition or stress grade. You say it worked up till now, so it must be O.K., and I suggest it probably wasn’t originally designed for 100psf and just hasn’t seen its design load plus.