To clarify / correct my previous discussion of results of the two previous simulations:
electricpete said:
With ground conductor is perfectly shorted to the pipe at each end, the flux solution is on slide 2, circulating current in groundwire and pipe is approx 18A (slides 3 and 4) and induced voltage is approx 0.3 vac (slide 5)
With ground conductor open (not connected at each end) as per slide 6, there is no circulating current and induced voltage is 0.5vac in the groundwire and 0.1 vac in the pipe.
Should have been:
corrected said:
With ground conductor is perfectly shorted to the pipe at each end, the flux solution is on slide 2, circulating current in groundwire and pipe is approx 18A (slides 3 and 4) induced voltage shown on slide 5 is end-to-end voltage... this voltage does not have much physical significance since it is difficult to measure... voltage measured by connecting test leads would depend on positions of the leads
With ground conductor open (not connected at each end) as per slide 6, there is no circulating current and induced voltage is 0.5vac in the groundwire and 0.1 vac in the pipe. The voltage measured at one end would be the vector difference of these two induced voltages (which is approx 0.5 vac)
waross said:
How about close up the spacing between the wires, they are generally twisted tight together. With .6 inch wires, the centers may be as little as .7inches.
Attached is another powerpoint with results of center-to-center distance reduced to 0.75” (that leaves 0.075” for insulation).
The short circuit result (slide 1) is |I| = |15.273 + j*7.339| = 16.94A.
(contrast to previous open circuit result: |I| = |115.506 + j* 9.26| = 18.06A).
The end-to-end voltage in short-circuited configuration on slide 2 as previously discussed... not much significance.
The open circuit results:
Slide 3: |Vgroundwire| = | | = 0.488608+0.2396i = 0.544 vac
Slide 4: |Vpipe| = -3.42E-003+1.95E-002i = 0.019 vac
Total Open Circuit Voltage = |Vgroundwire – Vpipe| = |0.492028+0.2201i| = 0.539 vac
(contrast to previous open cricuit result |V| = 0.49 vac
So moving the wires closer together did not significantly change the results, and in fact slightly reduced the open circuit voltage and short circuit current.... opposite the direction of effect needed to try to recreate the measured results of approx 90A short circuit and 15vac open circuit.
I think the next logical step would be to try moving the bundle of 4 conductors close to the edge and repeating the calculation. Since twist is not modeled, the resulting induced Voc and Isc will clearly be higher than if the twist were included. But it is still a useful excercize.... if the result is that the calculated Voc and Isc with twist neglected remain far less than measured, we might begin to conclude that induced voltage of this magnitude is not credible. If on the other hand, we exceed the measured values, then we need to sharpen our pencil on modeling the twist.
I just saw thewellguy's post... I can change the model to put the wires outside. Mark - do you know the configuration.
In either case, I think waross hit on an important subtle point that it certainly took me awhile to figure out... the location of the groundwire within the 4-wire twist is not symmetric with respect to all three phases and therefore there is an induced voltage. LPS for you.
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