Hello
I would like to add another comment, the aluminium wire is used due to cost reduction, the aluminium wire is cheaper than the copper, some practizal way to calculate the desired new mm2 copper wire is :
R= ρ L / A where ρ is resistivity L is lenght and A is area (mm2).
So for both materials:
R Cu = ρ Cu x L / S Cu and R Al = ρ Al x L / S Al
R / L is:
R Cu/ L = ρ Cu / S Cu y R Al / L = ρ Al/ S Al
ρ Cu / S Cu = ρ Al / S Al
Due to ρ Cu = 1.71 x 10-8 Ω-m and ρ Al = 2.82 x 10-8 Ω-m
The mm2 are :
S Cu = 1.71 x 10-8 x S Al / 2.82 x 10-8 or
S Cu = 0.606 x S Al
So for practical cases you can reduce two sizes when replace the aluminium, then a 17 AWG is replaced by 19 AWG.
But in my own practice I was replace the Al by Cu wire with the same AWG gauge so if we have 17 then I use 17, and this is supported in: 1. The same wire gauge don´t produce that space in the slot and further mechanical problems 2.The motor will run more cool and could support overloads(The effect is like you can increase two wire sizes in original copper winding) and 3. The 17 AWG wire cost is less than 19 AWG , small sizes are expensive than big ones.
Best Regards
Carlos