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Circlip resistance calculation

Faroukpin

Mechanical
May 22, 2025
2
Hello
I'm designing a stainless steel hinge with bronze bushings, and I've chosen to secure the pin using two E-type circlips.
I would like to know if the circlips can withstand the loads (which I don't know how to calculate).

I would like to create a calculation note to verify whether my design solution is suitable.

Could you help me, please?

Here are the conditions.

1747927445937.png
Here are the allowable forces specified by the circlip manufacturer.

1747927714446.png
 

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I can't understand how your hinge is supposed to work.

What are the orange parts?

Where is the pin?
 
The axial load on a typical door hinge pin is very close to zero. I have a door where the hinge pin defies gravity and moves up. It takes about 10 years to get to where it looks like a problem.
 
Why do you suppose there is any meaningful load on the circlips?

EDIT: And why are you not just buying hinges?

Regards

Mike
 
100kg is pretty heavy for a door. I agree determining the axial load on these pins is very nebulous, but
1) why not an off-the-shelf hinge ?
2) are a hinge producer make you a custom one (if you feel your needs are special) ?
3) just drop a bolt in, as a pin (what would cause the pin to migrate upwards significantly ?)
4) is there some security issue (like you don't want people to tamper with it) ?
 
Ok, so the orange parts are the bronze bushings.

You understand that only one of them is in the load path, right?

I still don't see a pin.
 
Two comments/questions:
1. The Circlips (called retaining rings by us old farts) should see ZERO load from the door! The hinge itself should absorb all that load. Your hinge pin should be designed so that the distance between the clips is slightly longer than the distance from top to bottom of the hinge.
2. Why are you even designing a hinge? There are SO MANY variations available on the market! If there is some reason that none of them would work, what is it?
 
Two comments/questions:
1. The Circlips (called retaining rings by us old farts) should see ZERO load from the door! The hinge itself should absorb all that load. Your hinge pin should be designed so that the distance between the clips is slightly longer than the distance from top to bottom of the hinge.
2. Why are you even designing a hinge? There are SO MANY variations available on the market! If there is some reason that none of them would work, what is it?
This is a request I received

I planned for some clearance for the circlips, but I haven’t defined it yet.

I wanted to know if the solution would work before moving forward with the design.
I can't use a bolt, a pin with a head is more expensive, and welding the pin is not very aesthetic. and Using a dowel pin is also more costly.
 
Last edited:
The FBD you posted earlier was wrong. Perhaps you realized that since you deleted it.

The moment caused by the weight of the door is reacted by horizontal forces at the two hinges.

Axial forces on hinge pins are negligible.
 
The FBD you posted earlier was wrong. Perhaps you realized that since you deleted it.

The moment caused by the weight of the door is reacted by horizontal forces at the two hinges.

Axial forces on hinge pins are negligible.
Let's discuss, and I am not saying I am correct.
Center mass of door. Mg force = -x,
There is a distance from center mass to center of hinge pin. Static loads from fasteners.
Causining shear load on pin.
Moment on the pin from swing of the force of door acting the pin. Am I on track?
 
shear on the pins is the couple due to the offset weight.
the weight itself is carried by the hinges themselves, bearing of of the two pieces of the hinge (door-side and wall-side) ... yes ?

I suspect someone asked this question "how is the weight of the door reacted ?"
and someone quickly answered "by the circlip" and the rest is history.

in fact, the circlip should be placed so it cannot bear against the hinge ... there will be a small, very small, tolerance between the hinge pieces, and the position of the circlip should ensure that it won't bear up.
 

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