OK guys, to prove I'm right, here's my version of Diaphragm 101:
Remember your mechanics of solids? In order to be statically stable, any isolated "element" has to have shear acting in both directions (opposing couples). That means there is not only vertical shear in the diaphragm, there is horizontal shear as well. At the "chord" edge of the diaphragm (the edge of our "element"), this horizontal shear has to be resisted (by something) for stability. That is where the "chord" comes in.
For a simple span diaphragm, the vertical shear at the support would be wL/2d (lbs/ft), where d is the depth of the diaphragm. Again, for stability, the horizontal shear in the diaphragm at any given point has to equal to the vertical shear in the diaphragm. This means the horizontal shear diagram is exactly the same as the vertical shear diagram: it is wL/2d at the supports, and zero at L/2. The change in chord force over any given distance is the area under the shear diagram. This chord force is zero at the supports, and increases to a maximum at the center, increasing more over a given distance near the support than towards the middle (larger area under the shear diagram per unit length the closer you get to the support).
If this chord force is unresisted by anything but, say, an edge angle, then the chord force at the center of the span would be wL/2d*L/2* 1/2(area under the shear diagram) = wL^2/8d (sounds familiar?). However, if the edge angle is intermittently connected over it's length to a shear wall/tilt-up that's hooked up to the ground, this chord force can (and will) dump out of the edge angle at each connection.
Just for an example, say w=300 lbs/ft, L=200', d=75' and your first connection along the chord is 6' from the support. The horizontal shear at the end is wL/2d = 300*200/(2*75)= 400 lbs. per foot. The area under the horizontal shear diagram between the support and 6' away is (400+(400-300*6/75))*0.5*6=2328 lbs. This is the chord force in the edge angle at this point. If all of this load can dump out in the first connection, and it probably can, then the chord force won't accumulate. If all connections are at no more than 6' on center, and they're all strong enough to transfer the change in chord force, the maximum force in the edge angle will never be greater than 2328 lbs! Of course, the shear wall/tilt-up has to be capable of resisting these loads and sending them to the ground (probably so).
This totally explains haynewp's comments about a cantilevered diaphragm. It's not that there aren't any chord forces, it's just that they don't build up, and are gone by the time you get to the diaphragm support. If the cantilevered diaphragm did not have shear walls on the "chord" edges... say, just steel beam & column framing with a vertical x-brace each side, you would build up significant chord forces, depending on the distance to the resisting brace along the "chord" wall.
Shear and bending/chord forces are not "apples & oranges". They go hand-in-hand.