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C&C Wind Load Effective Area

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medeek

Structural
Mar 16, 2013
1,104
As I'm going through the "Guide to the Wind Load Provisions of ASCE 7-10" by Mehta and Coulborne I noticed an inconsistency with the regard to the way the effective area for a roof panel is determined. In the one example the roof panel is a 4x8 plywood panel on 24" o/c spaced trusses with the eff. area given as 32 ft2. On the other example the roof panel is 2x8 spanning across trusses that are 48" o/c with the eff. area given as the larger of 4 x 2 = 8ft2 or (4*4)/3 = 5.3 ft2.

If the 4x8 sheet of plywood is spanning the trusses with the long axis perpendicular to the trusses (case 1) shouldn't the span then be 2 ft. The effective area would be the larger of either 2x4 = 8 ft2 or (2*2)/3 = 1.33 ft2.

When dealing with windows, doors and roof panels do you consider the actual area of the component or consider some spanning distance and then compare this distance squared divided by 3 to the trib area? I guess what to use as the effective area for some components had got me a little confused.
 
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Are the two examples designing the same "thing"? If the design is for the plywood itself, then perhaps the whole 32 in^2 is appropriate.

If you are checking the nailing, a smaller trib area.
If you are checking the rafter then another one as well.



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Agree with JAE...it depends on which part of the load application you are considering.
 
I'm often dealing with high wind locations and I like to check that the roof sheathing will be sufficient for out of plane loads (SDPWS 2008 Table 3.2.2). My concern is that I am calculating the correct wind force to compare against the allowables of this table. 90% of time the roof sheathing is either 7/16 OSB or 15/32 CDX APA rated plywood. The sheathing is typically installed with the strength axis perpendicular to the trusses or rafters. If I consider the span to be the 2 ft. between trusses then the effective area is only 8 ft^2 whereas if I consider the entire area of the panel then the effective area is 32 ft^2. The C&C wind loads are dependent on the eff. area and the difference between 10 ft^2 and 32 ft^2 is actually quite significant.
 
I think 32 SF is OK for checking the plywood and fasteners. A strict interpretation of the Code would result in designing just about any fastener on a typical project for the 10 SF C & C wind load--I just think this is too conservative.

For example, I do a lot of design of cold formed steel wall stud framing. I use the tributary area for an individual stud (usually H^2/3) to determine the C & C wind load for checking the stud AND connections. A typical slide clip connection which connects a stud to a steel superstructure will be fastened with 2, 3 or 4 fasteners. Should I check the slide clip for the 10 SF C & C load, since an individual fastener will have a tributary area less than 10 SF? Strictly speaking, yes, but I don't--too conservative.

DaveAtkins
 
I don't think of the span length necessarily, but the member. I am not going to fail a piece of OSB on the 2ft span, an entire sheet will have to come into play, so I use the full 32 ft^2. If I have a 30ft long roof truss I wouldn't expect the truss designer to check C&C pressures on a piece of chord between panel points (I sure wouldn't do it either).
 
The consensus here seems to be that interpreting the code to rigidly is over conservative and hence some engineering judgement comes into play.
 
Here is what I get for the C&C wind loads based on the preceeding conversation:

C&C Wind Loads - Job 2014-017

Note that the wind forces on the roof panel in zone 3 (overhang) is way up there 88 psf (ASD), but I suppose this is realistic.

Based on this and the APA publication Q225G the allowable for L/240 for 7/16" OSB is only 51 psf. This would then require a thicker sheathing (ie. 15/32 Plywood) which gives a 81 ps allowable for the same spacing and deflection requirement. Note, that this allowable is still below the 88 psf however I think some judgement needs to come into play here otherwise this roof would cost a fortune to sheath.
 
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