If you assume you both the existing and the increased pressure are in the gas phase, and the volume (body cavity) is constant, eg the gas is enclosed in a thight vessel, you can use the combined gas law: p1*v1/t1=p2*v2/t2. v1 = v2 and will cancel out, and p1 and p2 are known and in the saame denomination. T1 and T2 are in degrees absoulute (deg. Kelvin ca 273 plus deg C). Solved you will get T2 = 1,44 * T1. This will be the worst case, leakage to a lesser pressure will lower the cavity pressure.