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Beam Reinforcement Calculation

Nick6781

Structural
Joined
May 15, 2024
Messages
52
Location
CA
Let's say I need to use a web plate instead of a flange cover plate (I know...) to reinforce a beam. How do I calculate the required weld to ensure the section acts compositely? The shear flow equation gives the shear along a horizontal plane, but in this case, the faying surface is vertical. I can't quite wrap my head around it.




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CANPRO argues my point in that thread. The Ix of the combined section is simply the sum of the I of the beam and plates. If there was actual shear flow, the Ix of the composite section would be greater than the sum of the individual Ix's.
Thanks for sharing that thread. Appreciate @CANPRO going all in for that discussion.

Who knew shear flow was such a hotly contested subject here on eng-tips.
 
Well, it can be a bit more complicated than you might think. I would tend to agree that there is no shear flow for the OP's shape (or for the one in the referenced thread) provided the side plates or channels are carried to the supports. But usually, when side plates are added to reinforce a beam, they are not extended over the full span, so it helps to understand the shear flow formula. Each side plate puts a reaction on the beam which is very small for side plates, but not so small for side channels or other more substantial welded reinforcements.

Another complication with shear flow occurs when we design beams stressed beyond the elastic range. The factored moment M = phi*Z*Fy (Z is the plastic modulus). That may render the formula VQ/I inaccurate for part of the beam because 'I' is an elastic property.

Within the elastic range, using the shear flow formula appears to be conservative.
 
Well, it can be a bit more complicated than you might think. I would tend to agree that there is no shear flow for the OP's shape (or for the one in the referenced thread) provided the side plates or channels are carried to the supports. But usually, when side plates are added to reinforce a beam, they are not extended over the full span, so it helps to understand the shear flow formula. Each side plate puts a reaction on the beam which is very small for side plates, but not so small for side channels or other more substantial welded reinforcements.
But while it remains a symmetric member about the neutral axis there still is no longitudinal shear flow, even for "side channels or other more substantial welded reinforcements".

Another complication with shear flow occurs when we design beams stressed beyond the elastic range. The factored moment M = phi*Z*Fy (Z is the plastic modulus). That may render the formula VQ/I inaccurate for part of the beam because 'I' is an elastic property.
I disagree. 'I' is not an "elastic property" it is a geometric property. And unless the geometry of the section changes then 'I' won't change (Any plastic deformation isn't going to change the geometry significantly). Thus VQ/I doesn't become inaccurate in the plastic range.

Within the elastic range, using the shear flow formula appears to be conservative.
I'm not sure what you mean here. The shear flow formula for this example calculates out to ZERO as Q = 0.

The formula is neither conservative nor unconservative it is an exact formula from mathematical analysis.

Circling back to this:
Yes, there is. VQ/I is the shear flow for the existing beam plus two new plates where Q is taken at top (or bottom) of added plates.

If w is web thickness and t is the added plate thickness, then each weld must resist VQ/I * t/(w+2t).

It turns out that Q is unchanged by the addition of two plates, but Icomp = Ibeam + 2tddd/12 where d is plate depth.
Q is not unchanged, it is zero. As you measure the center of area of the plate to the centroid of the beam. This gives a value of 0.
 
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I am sorry but i disagree with this comment. If the beam loaded say UDL , and if the shear force is not zero, there will be horizontal shear flow.Staggered fillet welding could be OK but it is necessary to dictate combined behavior of the section.
Why do you assert this when it goes against the theory and shear flow formula and the previously explained points?

I am sorry but i disagree with this comment. If the beam loaded say UDL , and if the shear force is not zero, there will be horizontal shear flow.Staggered fillet welding could be OK but it is necessary to dictate combined behavior of the section.
The section will behave in a combined manner purely on vertical shear transfer. Provide staggered bolts with horizontal slots and you'll have 'combined behaviour'. Both beams will deflect in unison and the added plates will provide resistance to bending.
 
But while it remains a symmetric member about the neutral axis there still is no longitudinal shear flow, even for "side channels or other more substantial welded reinforcements".
You are wrong. There is shear flow for every beam, even a simple rectangular beam.
I disagree. 'I' is not an "elastic property" it is a geometric property. And unless the geometry of the section changes then 'I' won't change (Any plastic deformation isn't going to change the geometry significantly). Thus VQ/I doesn't become inaccurate in the plastic range.
Again, you are bloody wrong! It is a geometric property which is used in the elastic range, not the plastic range.
I'm not sure what you mean here. The shear flow formula for this example calculates out to ZERO as Q = 0.

Q is not 0 for a beam with side plates. In fact, it is not 0 for any beam.

The formula is neither conservative nor unconservative it is an exact formula from mathematical analysis.
It is exact within the elastic range. It is not exact in the plastic range.
Circling back to this:

Q is not unchanged, it is zero. As you measure the center of area of the plate to the centroid of the beam. This gives a value of 0.
Q is not zero at the neutral axis, it is not zero where the web meets the flange, and it is not zero anywhere in between. I suggest you read a strength of materials textbook for the definition of Q..
 
You are wrong. There is shear flow for every beam, even a simple rectangular beam.
Well that is stating the obvious. Since we are being pedantic I should have said there is not longitudinal shear flow BETWEEN the members. In this case the beam and the plates.

Again, you are bloody wrong! It is a geometric property which is used in the elastic range, not the plastic range.
It is a geometric property (have a look at any basic definition) that exists inside the elastic range and in the plastic range. It isn't a property that disappears if there is plastic deformation. If you are referring to the EI formula to determine stiffness it is the E that effectively changes. The 'I' remains the same as long as the section retains its geometric shape.

Q is not 0 for a beam with side plates. In fact, it is not 0 for any beam.
Again I'll refer to the first line from wikipedia. "The first moment of area is based on the mathematical construct moments in metric spaces. It is a measure of the spatial distribution of a shape in relation to an axis."

In this case the axis is neutral axis. Perform calculation for the entire plate relative the the system and due to symmetry there is no longitudinal shear flow BETWEEN the plate and the web.

It is exact within the elastic range. It is not exact in the plastic range.
You keep asserting this without any explanation.
 
Well that is stating the obvious. Since we are being pedantic I should have said there is not longitudinal shear flow BETWEEN the members. In this case the beam and the plates.
Yes there is.
It is a geometric property (have a look at any basic definition) that exists inside the elastic range and in the plastic range. It isn't a property that disappears if there is plastic deformation. If you are referring to the EI formula to determine stiffness it is the E that effectively changes. The 'I' remains the same as long as the section retains its geometric shape.
My/I is not correct for stress in the plastic range.
Again I'll refer to the first line from wikipedia. "The first moment of area is based on the mathematical construct moments in metric spaces. It is a measure of the spatial distribution of a shape in relation to an axis."

In this case the axis is neutral axis. Perform calculation for the entire plate relative the the system and due to symmetry there is no longitudinal shear flow BETWEEN the plate and
Here are a few 'q' values for your amusement. Note that q at y=2 is unchanged by the presence of side plates.
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the web.


You keep asserting this without any explanation.
The explanation is that moment of inertia is the wrong property to use in the plastic or partial plastic range.
 
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For those who like to see visuals and let computers do the work. Here is my representation of a beam with plates under UDL. I have an I-beam and two symmetrical plates with a rigid fastener staggered along the beam.


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BELOW WE HAVE THE SHEAR FOR DIAGRAM SHOWING NO LONGITUDINAL SHEAR TRANSFER BETWEEN THE BEAM AND THE PLATES.

1751411304494.png

AND BELOW IS WHAT HAPPENS WHEN I OFFSET THE PLATES IN THE VERTICAL DERIECTION WE GET LONGITUDINAL SHEAR TRANSFER AS EXPECTED. INCREASING TOWARDS THE ENDS AS EXPECTED.

1751411474511.png
 
I'm not sure how that relates to this thread, but I will think about it.
 
I'm not sure how that relates to this thread, but I will think about it.
It relates because it shows the shear flow between the plates and the beam which is exactly the original question. It shows no longitudinal shear flow. In the second image I offset the plates to check that the model behaves as theory would expect, which it does.

Of course in all this discussion there longitudinal shear flow within the beam and the plates. But we don't care about that we only care about the shear flow BETWEEN the plates and the beam.
 
Shear flow BETWEEN plates and beam is not defined. The plates are welded to the web of the beam. We need to think of the red and blue plates on my sketch as a composite unit. We care about the strength of weld required to generate the shear flow in the blue plates (which is not zero).

I do not understand your recent presentation at all, but perhaps my poor old brain needs a rest.
 
It relates because it shows the shear flow between the plates and the beam which is exactly the original question. It shows no longitudinal shear flow. In the second image I offset the plates to check that the model behaves as theory would expect, which it does.

Of course in all this discussion there longitudinal shear flow within the beam and the plates. But we don't care about that we only care about the shear flow BETWEEN the plates and the beam.


Here are a few 'q' values for your amusement. Note that q at y=2 is unchanged by the presence of side plate
I din't respond to this point earlier as I didn't know what or how your were calculating things. And I still don't. But it seems you have a non zero value for when y=0 which presumably is the at the centroid. But this flies in the face of the one of the definition of the centroid as the location where the first moment of are are equal to zero.
 

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