A chamfer symbol?

[jerry1423]

I recently started a job where the symbol for a chamfer on a drawing is an equilateral triangle. It is placed on the dimension similar to a diameter symbol is with a hole.
I have never seen that before, and I cannot find it in any drafting standard.

Has anybody else seen the symbol for a chamfer being an equilateral triangle?

 

[MadMango]

I have never seen that, at least not in the ASME world.

"Art without engineering is dreaming; Engineering without art is calculating."

Have you read faq731-376 to make the best use of these Forums?

 

[fcsuper]

I've also not seen that before. Not only that, it seems rather redundant to the chamfer callout as the symbol adds no information that is already there. It is confusing to me because a chamfer is the last thing I would think of if I saw a triangle.

Matt Lorono
Lorono's SolidWorks Resources & SolidWorks Legion

http://groups.yahoo.com/group/solidworks & http://twitter.com/fcsuper

 

[ctopher]

I seems familiar in old school. I think I may have seen a guy use it maybe 25 years go. Not part of any standard that I know of.

Chris
SolidWorks 09 SP4.1
ctopher's home
SolidWorks Legion

 

[jerry1423]

I think old school would explain it. It seems like they are trying to move forward here, but there are little things (such as this chamfer symbol) that they are not letting go.
There are engineers that have been here 40 years (more or less) so I can understand why they do "old school" things like this, but the reluctance to go with a standard (either ISO or ANSI) is something that I just don't understand - it's like a child getting rid of his blanket.
Thank you for your replies.

 

[MadMango]

I did a Google Image Search and ran across an image of an old school drawing that used a diamond to indicate a chamfer on the end of a rod (value inside diamond). That didn't make any sense either, but made more sense that the triangle.

Don't contiue the bad habits, stick to the Standards.

"Art without engineering is dreaming; Engineering without art is calculating."

Have you read faq731-376 to make the best use of these Forums?