Tek-Tips is the largest IT community on the Internet today!
Members share and learn making Tek-Tips Forums the best source of peer-reviewed technical information on the Internet!
-
Congratulations JAE on being selected by the Eng-Tips community for having the most helpful posts in the forums last week. Way to Go!
Allowable shear load SAE Grade 5 bolt
- Thread starter spike
- Start date
SAE Grade 5 medium carbon steel quenched and tempered
1/4 thru 1 inch Yield (psi)=92,000 Ultimate Tensile Strength (psi)=120,000
One method used to calculate the value is the American Institute of Steel Construction (AISC) Manual of Steel Construction, Allowable Stress Design. Using this method, the allowable tensile stress, Ft, and the allowable shear
stress, Fv, are calculated as follows:
Ft = 0.33 x Fu
Fv = 0.17 x Fu
Where Fu = minimum specified ultimate tensile
strength for the steel material.
This stress is then applied to the gross nominal area of the threaded section to calculate the load in pounds.
See spreadsheet at:
also
Mil-Handbook 5 list Fv = 0.60 x Fu
1/4 thru 1 inch Yield (psi)=92,000 Ultimate Tensile Strength (psi)=120,000
One method used to calculate the value is the American Institute of Steel Construction (AISC) Manual of Steel Construction, Allowable Stress Design. Using this method, the allowable tensile stress, Ft, and the allowable shear
stress, Fv, are calculated as follows:
Ft = 0.33 x Fu
Fv = 0.17 x Fu
Where Fu = minimum specified ultimate tensile
strength for the steel material.
This stress is then applied to the gross nominal area of the threaded section to calculate the load in pounds.
See spreadsheet at:
also
Mil-Handbook 5 list Fv = 0.60 x Fu
- Status
Similar threads
- Question
- Question
- Locked
- Question
- Locked
- Question