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Decomposition of solute concentration in Fe-Cr-C alloy

Decomposition of solute concentration in Fe-Cr-C alloy

(OP)
Say, I have a 0.1 % C and 18 % Cr in a Fe-alloy. At a particular temperature, we have precipitate formation (of Cr23C6), eating many Cr atoms. At a given temperature , How do I evaluate the remaining Cr atoms in the alloy ?

RE: Decomposition of solute concentration in Fe-Cr-C alloy

The rest of the Cr atoms will be just fine. They are not the weak link.

"Everyone is entitled to their own opinions, but they are not entitled to their own facts."

RE: Decomposition of solute concentration in Fe-Cr-C alloy

Convert to atomic percent, multiply C x 23/6 to figure out how much Cr is tied up.
The subtract from the original C and convert back to wt%.

= = = = = = = = = = = = = = = = = = = =
P.E. Metallurgy, consulting work welcomed

RE: Decomposition of solute concentration in Fe-Cr-C alloy

I've done that math previously, and a little C can tie up a whole lot of Cr in terms of percent mass!

"Everyone is entitled to their own opinions, but they are not entitled to their own facts."

RE: Decomposition of solute concentration in Fe-Cr-C alloy

So roughly 52/12 x 010 = 0.43 wt % Cr

= = = = = = = = = = = = = = = = = = = =
P.E. Metallurgy, consulting work welcomed

RE: Decomposition of solute concentration in Fe-Cr-C alloy

0.10 x 23/6 x 52/12 = 1.66

(wt% C x Atomic ratio x Atomic weight ratio = wt% Cr)

"Everyone is entitled to their own opinions, but they are not entitled to their own facts."

RE: Decomposition of solute concentration in Fe-Cr-C alloy

duh, thanks IM.

= = = = = = = = = = = = = = = = = = = =
P.E. Metallurgy, consulting work welcomed

RE: Decomposition of solute concentration in Fe-Cr-C alloy

First thing I've ever seen you get wrong, Ed!

(It's always the simplest question on the exam I screw up.)

"Everyone is entitled to their own opinions, but they are not entitled to their own facts."

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