I am working on a crude oil terminal in salt caverns. The caverns are either filled with crude or with brine. The brine is pumped into the cavern to displace the crude. The brine water has a SG of 1.2 and the crude oil 0.86. The brine pumps are about 6000 ft from the cavern with about a 0.3 psi/100 ft pressure loss (equals ~20 psi line loss) to the cavern. The line that enters the cavern is 6500 ft (about another 20 psi line loss) down into the cavern. Assuming the cavern is full of crude oil, what pressure will you need to pump the brine? The brine is much denser then the crude, therefore, I assume once it is over the edge of the cavern, the brine weight overcomes the crude and not a lot of pressure is needed. Is my assumption correct? I am having a hard time putting this into my pump calculation program. Can I assume the cavern is at 0 psig at the entrance of the brine side? Also, the pressure the crude needs to come in would be line losses plus 6500ft*(74.88 lb/ft3-53.6 lb/ft3)/144in2/ft2=960 psig. Does anyone have experience on this topic?
Red Flag Submitted
Thank you for helping keep Eng-Tips Forums free from inappropriate posts. The Eng-Tips staff will check this out and take appropriate action.
Reply To This Thread
Posting in the Eng-Tips forums is a member-only feature.