Join two bridges by a common ground
Join two bridges by a common ground
(OP)
Please view the uploaded picture.
There are three GND on the schematic, two of them belonging to a bridge rectifier with different power handling. I would like to join all of them without making a firework
Is it possible ?
If I don't join them I don't know how to make the switching transistor work
The first bridge and the IC are already connected and working together very well
Please notice the AC blocking capacitor before the first bridge (as probably noted, there are no transformers)
Also, ignore the AC lines connected to the butts of the diodes instead of their head
(The schematic is out of date. The 555 was replaced by an OP Amp, and the blocking capacitor is 330nF. The components values are dummies, not yet calculated)
There are three GND on the schematic, two of them belonging to a bridge rectifier with different power handling. I would like to join all of them without making a firework
Is it possible ?
If I don't join them I don't know how to make the switching transistor work
The first bridge and the IC are already connected and working together very well
Please notice the AC blocking capacitor before the first bridge (as probably noted, there are no transformers)
Also, ignore the AC lines connected to the butts of the diodes instead of their head
(The schematic is out of date. The 555 was replaced by an OP Amp, and the blocking capacitor is 330nF. The components values are dummies, not yet calculated)
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RE: Join two bridges by a common ground
Can you use an opto as a level shifter to drive the transistor? If would likely be easier to drive a FET rather than a BJT unless the switching frequency is very high.
RE: Join two bridges by a common ground
I'll use an optocoupler I might have around
This high voltage transistor was chosen based on availability (stole it from CFL bulbs)
They're switching oriented
I was planning on work at 100kHz. Says the datasheet "Transition Frequency" >= 4.0MHz
I'm not sure if this information is what I think it is.
Would you kindly help me finding this information on the datasheet ?
There's a link below
Also, I fail to see the dynamic here. I thought the second half-cycle was equal to the first. On both cases the current flowing on the same directions
If you could elucidate this part. I'd also be grateful
And finally,
Is there another alternative instead of an optocoupler ?
No problem in redesigning everything from scratch
I've got four power sources to do, and one opto. Also, this opto does 60V, not 127 (the transistor is supposed to buck)
http://www.rectron.com/data_sheets/cd13002.pdf
RE: Join two bridges by a common ground
RE: Join two bridges by a common ground
Since the thread is still up...
Let's leave the transistor and the logic of the power supply behind
This part I'll do the empirical way
Because I think I really need the lesson on why I cannot join the goddam bridges
I fail to see a reason
Both inputs are phased... Both grounds are transmitting in the same direction on any part of the cycle...
I cannot see the problem in theory (only ¡plaac! and smoke in practice)
RE: Join two bridges by a common ground
The D4 cathode and D10 cathodes will be 0.7V below their respective grounds. If you link the two grounds then the drop across C3 will be zero and a lot of current will flow through D1, D6, and D10. There's a good chance that D6 will get hot. And then explode. It might get saved by D1 or D10 exploding first.
Try it and see. Include a fuse somewhere.
RE: Join two bridges by a common ground
Now I understand
That was the missing explanation
And my carbonized testing board confirmed twice it doesn't work
Forgot the fuses
Thank you again
RE: Join two bridges by a common ground