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Programming an iterative loop

Programming an iterative loop

Programming an iterative loop

(OP)
Hello everyone,
I am new in programming with Mathcad, as up to now I have only used it for simple calculations. I now want to solve an energy balance which needs to be solved iteratively. The error I get is not enough memory for this peration but I am guessing I am doing something wrong with arrays. Apart from that, I am also wondering whether my way of thinking is the wrong one for Mathcad, since I am trying to solve it in the same way I do it in Matlab.
I would really appreciate any help.
El.

RE: Programming an iterative loop

Your getting a memory because your loop hasn't ended after 23 iterations.

Your "while loop" counter needs to be inside the "while loop" syntax

i.e : t <-- t + 1

However from looking at your program I don't think it will work as intended.

Dave, Msc(Eng), AMIMechE
Graduate Mechanical Engineer
(3 Years left for Chartership!)

RE: Programming an iterative loop

Apologies for the typos, i really should proof read more, it was indeed in my last appraisal.

*You're getting a memory error...

Dave, Msc(Eng), AMIMechE
Graduate Mechanical Engineer
(3 Years left for Chartership!)

RE: Programming an iterative loop

Not to discourage you from programming, but the problem doesn't really need a program loop. It looks to be solvable with Given-Find or Minerr, which are described in the Help entries. They will do the iterative solution on their own; you simply need to provide guess values and all the constraints.

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RE: Programming an iterative loop

I agree with IRstuff, read up on the "Find" capability and try to re-write it. Once I learned to use it, it has come in very handy.

RE: Programming an iterative loop

(OP)
Dear all,
Thank you very much for taking the time to have a look at my problem. I had tried to use the given/find way, however I couldn't make it work and I thought it could be because I am looking to find the solution as a function of time. I will try it again and see how it goes.
Thanks again,
El

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