How to test and average the surrounding non-zeros elements

Hi guys,

Here is the problem:

Say if I have a matrix that looks like:

new_x =

0 0 0 0 0
0 0 **9.0000** 9.0000 0
0 4.0000 9.0000 **9.0000** 0
0 **8.3333** **8.0000** 0 0
0 2.0000 4.0000 8.0000 0
0 4.0000 5.0000 8.0000 0
0 0 0 0 0

Where **value** means the centre.

I want to test if the neighbor elements are equal, lesser, or greater than the centre. If it is greater or equal then '1' or else '0'. The neighbor elements depend on the radius.

For example,

For radius =1 m = 1 element away from the centre, test_x = [(i+1,j) , (i-1,j) , (i,j+1) and (i,j-1)] - top, bottom, right, and left of the centre.

For radius =2 m = 2 elements away, test_x = [(i+1,j), (i+2,j) , (i-1,j) , (i-2,j), (i,j+1), (i,j+2), (i,j-1), (i,j-2), (i+1,j+1), (i+1,j-1), (i-1,j-1), and (i-1,j+1)].


Note: if the neighbors are with in the radius of the two or more centres, take the smallest centre average to test.

0 12 9
4 **9** 15
11 19 0

The '9' in the middle is within the radius of 12, 15, and 19 centres, so take the minimum average of those min[9.000, 9.000, 8.000]=8.000

For example, when radius = 1 m or 1 element away.

new_x =

0 0 0 0 0
0 0 **9.0000** 9.0000 0
0 4.0000 9.0000 **9.0000** 0
0 **8.3333** **8.0000** 0 0
0 2.0000 4.0000 8.0000 0
0 4.0000 5.0000 8.0000 0
0 0 0 0 0

Test_x =

0 0 0 0 0
0 0 **9.0000** 1 0
0 0 1 **9.0000** 0
0 **8.3333** **8.0000** 0 0
0 0 0 0 0
0 0 0 0 0
0 0 0 0 0


I have tried a few things before, however I am not familiar with the functions.

So please help me to solve the problem.

Thank you in advance.