Aluminum Strain Hardening Exponent

Question

Aluminum Strain Hardening Exponent

nickjk (Mechanical)

(OP)

13 May 10 13:04

Could anyone please help me to find the strain hardening exponent for 7075 T6, 6061 T6 and 2014 T6 Aluminum.

Thank you in Advance

NickJK

metengr (Materials) · Answer 1 · 2010-05-13 13:46:33

From ASM Handbook, Volume 8, Mechanical Testing and Evaluation, under Component testing,,,,,

7075 T6 monotonic load, n=0.113
6061 data for T651 only, monotonic load, n=0.042
2014 T6 not reported

nickjk (Mechanical) · Answer 2 · 2010-05-14 09:02:22

Metengr,

Thank you so very much for the quick response and location of the data.

NickJK

TVP (Materials) · Answer 3 · 2010-05-14 10:27:52

Aluminum alloys have a FCC crystal structure and low stacking fault energy, which means that dislocation cross slip is extensive, and therefore they do not significantly strain harden. 2014-T6 will be in the same range as the other two alloys, probably closer to 7075.

metengr (Materials) · Answer 4 · 2010-05-14 11:00:57

I found the reference below and it looks like the strain hardening exponent reported for 2014-T6 is 0.064 +/- .003

http://books.google.com/books?id=xEiAqMCXaA8C&pg=PA94&lpg=PA94&dq=strain+hardening+exponent+for+2014+T6+aluminum&source=bl&;ots=BIiuNiOGya&sig=eE4iZXS5N4DM-43mzxiKP1Hf-Jk&hl=en&ei=XWTtS6P6AoP78Aaev939Cg&sa=X&oi=book_result&ct=result#v=onepage&q=strain%20hardening%20exponent%20for%202014%20T6%20aluminum&f=false

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Aluminum Strain Hardening Exponent