Excel macro - Vlookup

• Apr 15, 2002

• #2

ivymike

Mechanical

Nov 9, 2000

5,653

US

IsNA() is a worksheet function if I'm not mistaken, so try

If (WorksheetFunction.IsNA(WorksheetFunction.VLookup(r, Range4, 2, False))) Then
Range("X5&quot.Offset(counter, 0).Value = "0A"
Else
Range("X5&quot.Offset(counter, 0).Value = "0B"
End If


Seems like you already knew how to do that.

 

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• Apr 15, 2002

• Thread starter
• #3

bigb

Mechanical

Sep 17, 2002

12

US

Hi
I tried Worksheetfunction.IsNA() but it does not work.

The problem here is because Vlookup does not return the value and hence there is is error. I am not able to capture it even though I tried your method Could you suggest me another method/ code?

Thanks!!!!
BigB

 

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• Apr 15, 2002

• #4

msmith

Materials

Mar 25, 2002

76

US

BigB,

See my post to your question in VBA Forum.

 

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• May 16, 2002

• #5

suggest

Mechanical

Jul 22, 2006

2

IN

BigB,

I'm not a VB user, but assuming that the syntax is similar in Excel formulas, shouldn't the IF statement have an ending parenthesis at the end of the line (and 1 less after 'False')? If it is correct as you entered, please respond so that I'll know better as I venture into VB.

 

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• May 16, 2002

• #6

msmith

Materials

Mar 25, 2002

76

US

suggest,

I'll answer for BigB since he doesn't have this thread marked for email notification and as it is somewhat old probably won't be monitoring it.

His IF statement is correct as written. There are three open parentheses balanced by three close parens. The outermost set actually serve no purpose and could be removed in this case.

The problem with BigB's function is related to a quirk in Excel VBA. Some worksheet functions will not work if you use

Code:

Application.WorksheetFunction.FunctionName

, or

Code:

WorksheetFunction.FunctionName

, but will using the syntax

Code:

Application.FunctionName

Hope this clears things up.

Regards,
M. Smith

 

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• May 16, 2002

• #7

suggest

Mechanical

Jul 22, 2006

2

IN

msmith,

Thanks for the input. It raises a few more questions regarding the WorksheetFunction issue, but that's what learning is all about!

 

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